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sleet_krkn [62]
4 years ago
5

When is an object that has been dropped from a great height through the air closest to vein in a free fall?

Physics
2 answers:
Elza [17]4 years ago
7 0
-- "Free fall" means no forces acting on the object except for gravity.

-- An object dropped through air has two forces on it -- gravity and air resistance.

-- So we're looking for the part of the drop where air resistance is smallest.

-- The force of air resistance depends on the speed through the air, so the
force of air resistance is smallest when <em>velocity downward is smallest</em>.



Degger [83]4 years ago
6 0

If there were no air, the object would be in free fall the entire time, and there would be no "terminal velocity". So, the object is closest to being in free fall when the effects of the air are minimized--and that is when the object has the smallest speed relative to the air.

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3 years ago
Rapid energy transfer between ____ and ____ energy make roller coasters thrilling
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The answer is the following:

Rapid energy transfer between Potential and Kinetic energy makes roller coasters thrilling. 

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Kinetic Energy is the energy related to the speed of the roller coaster cart. When the cart is at the highest point, the kinetic energy is at a minimum, but as it begins to go down, the Potential Energy is transformed into Kinetic Energy, making the cart to increase its speed and making it a thrilling experience. 
4 0
3 years ago
You can see lightning before you can hear the thunder. Which is the best explanation for this?
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8 0
3 years ago
Read 2 more answers
a .6 kg ball has a speed of 2 m/s at point a and kinetic energy of 7.5 j at point b. determine the following: the balls speed
Vladimir79 [104]

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3 0
4 years ago
The baseball weighs 1 kg. The pitcher throws the ball at a velocity of 10 m/s straight up. Neglecting air resistance, what is th
photoshop1234 [79]

Answer:

9.81 N

Explanation:

Given that a baseball weighs 1 kg. The pitcher throws the ball at a velocity of 10 m/s straight up. Neglecting air resistance. The maximum height reached will be calculated by using the formula

V^2 = U^2 - 2gH

U = 10 m/s

g = 9.8m/s^2

At maximum height, V = 0

Substitute u and g into the formula

0 = 10^2 - 2 × 9.8 × H

19.6H = 100

H = 100/19.6

H = 5.1 m

The Kinetic energy on the ball will be

K.E = 1/2mv^2

K.E = 1/2 × 1 × 10^2

K.E = 1/2 × 100

K.E = 50 J

But energy = work done

WD = Force × distance (height)

The force that acts on the baseball when it is HALF WAY to the top of the path will be

F × 5.1/2 = 50

F = 100/5.1

F = 19.61 N

The weight acting downward will be

W = mg

W = 1 × 9.8

W = 9.8 N

The net force acting on the ball will be

Net force = F - W

Net force = 19.61 - 9.8

Net force = 9.81 N

Therefore, the net force that acts on the baseball when it is HALF WAY to the top of the path is 9.81 N

4 0
3 years ago
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