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sleet_krkn [62]
3 years ago
5

When is an object that has been dropped from a great height through the air closest to vein in a free fall?

Physics
2 answers:
Elza [17]3 years ago
7 0
-- "Free fall" means no forces acting on the object except for gravity.

-- An object dropped through air has two forces on it -- gravity and air resistance.

-- So we're looking for the part of the drop where air resistance is smallest.

-- The force of air resistance depends on the speed through the air, so the
force of air resistance is smallest when <em>velocity downward is smallest</em>.



Degger [83]3 years ago
6 0

If there were no air, the object would be in free fall the entire time, and there would be no "terminal velocity". So, the object is closest to being in free fall when the effects of the air are minimized--and that is when the object has the smallest speed relative to the air.

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sammy [17]

Answer and Explanation:

Data provided in the question

Carbon mass = m

Initial speed = v_i

Coefficient = μk

Based on the above information, the expressions are as follows

a. By using the energy considerations the expression for the carton moving distance is

As we know that

Fd = \frac{1}{2} m (v_i^2- v_f^2)

where,

v_f = 0

F = u_kmg

(\mu_kg) d = \frac{1}{2} m v_i^2

d = \frac{\frac{1}{2}v_i^2}{\mu_kg}

d = \frac{v_i^2}{2 \mu_kg}

b. The initial speed of the carton if the factor of 3 risen, so the expression is

v_i^1 = 3v_i

d^i = \frac{(3v_i^2)}{2\mu_kg}

= \frac{9v_i^2}{2\mu_kg}

d^i = 9(d)

8 0
3 years ago
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Dima020 [189]
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3 0
3 years ago
Which of the following quantities is inversely proportional to the gravitational pull between two objects?
Contact [7]

Answer:

C

Explanation:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces

I hope this helps a little bit

7 0
3 years ago
Read 2 more answers
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