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mr Goodwill [35]
2 years ago
14

Which of the following statements is false about the distances between planets earth and the sun

Physics
2 answers:
KATRIN_1 [288]2 years ago
7 0
The distance from the sun to Neptune is about the same as the distance from Neptune to the next closest star, Proxima Centauri
Alexus [3.1K]2 years ago
3 0

Answer;

The distance from the sun to Neptune is about the same as the distance from Neptune to the next closest star, Proxima Centauri

Explanation;

When a planet like earth is closer to the sun the heat of the sunlight warms the surface of the planet hence,a planet like Neptune is far away from sun, the sunlight can't reach the planet and it's surface becomes cold so,the distance of the sun and planet is the main factor effecting the temperature.

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The speed of a sound wave traveling through air is 400 meters per second. The wavelength of the wave is 25 meters What is the
sweet [91]

Answer:

16Hz

Explanation:

Given parameters:

Speed of sound  = 400m/s

Wavelength  = 25m

Unknown:

Frequency of the wave  = ?

Solution:

To solve this problem;

      V  = F ∧  

V is the velocity

F is the frequency

∧ is the wavelength

      400  = F x 25

        F  = 16Hz

7 0
2 years ago
Read 2 more answers
A wave passes along the surface of the water in a ripple tank. Describe the motion of a molecule on the surface as the water pas
laila [671]

Answer:

Explanation:

Water waves are generally a transverse wave which do not cause permanent displacement of molecules of the medium. Transverse waves are waves in which the direction of propagation of the wave is perpendicular to the direction of vibration of the particles of the medium.

As the wave propagates from one point to another on the surface of water transferring energy, a molecule of water on its surface vibrates upwards and downwards. Its motion is perpendicular to the direction of propagation of the wave. After the vibration, it comes back to its initial position.

8 0
2 years ago
a 360 mile trip began on a greeway in a car traveling at 62 mph. Once the road became a 2 lane highway, the car slowed to 54 mph
Daniel [21]

Answer:

Time spent on the greenway road  = 4.5 hours

Time spent on the 2 lane road = 1.5 hours

Explanation:

The distance of the trip  is 360 miles and the initial speed of the car is 62 miles/hr and after the road became 2 lane highway the car slowed to 54 miles/hr.

Let us divide the trip into two

Greenway

speed = distance/time

speed = 62 mph

time = a

distance = speed × time

distance = 62a

2 lane highway

speed = distance/time

speed = 54 mph

time = b

distance = speed × time

distance = 54b

Total distance

62a + 54b = 360......................(i)

Total time

a + b = 6..............................(ii)

a = 6-b

insert a in equation (i)

62(6-b) + 54b = 360

372  - 62b + 54b = 360

-8b = 360-372

-8b = - 12

b = 12/8

b = 1.5

from equation (ii)

a + 1.5 = 6

a = 6 - 1.5

a = 4.5

8 0
2 years ago
The total resistance of resistors in parallel is always _________ the sum of the resistors.
docker41 [41]
A. less than

In fact, the resistance will be less than that of the lowest resistance resistor.
7 0
3 years ago
Read 2 more answers
A projectile is launched from ground level at an angle of 30 degrees above the horizontal. Neglect air resistance and consider t
Oduvanchick [21]

Answer:

just before landing the ground

Explanation:

Let the velocity of projection is u and the angle of projection is 30°.

Let T is the time of flight and R is the horizontal distance traveled. As there is no force acting in horizontal direction, so the horizontal velocity remains constant. Let the particle hits the ground with velocity v.

initial horizontal component of velocity, ux = u Cos 30

initial vertical component of velocity, uy = u Sin 30

Time of flight is given by

T = \frac{2u Sin\theta }{g}

Final horizontal component of velocity, vx = ux = u Cos 30

Let vy is teh final vertical component of velocity.

Use first equation of motion

vy = uy - gT

v_{y}=u_{y}- g \times \frac{2u Sin\theta }{g}

v_{y}=u Sin 30 - 2u Sin 30

vy = - u Sin 30

The magnitude of final velocity is given by

v = \sqrt{v_{x}^{2}+v_{y}^{2}}

v = \sqrt{\left (uCos 30  \right )^{2}+\left (uSin 30  \right )^{2}}

v = u

Thus, the velocity is same as it just reaches the ground.

6 0
3 years ago
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