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tamaranim1 [39]
3 years ago
13

a) 500. J of work are done on a system in a process that decreases the system’s thermal energy by 200. J. How much energy is tra

nsferred as heat? Is the transfer into the system or out of thesystem?(b) What is the heat transfer if the system’s internal energy instead increases by 200. J? Into or out of the system?
Physics
1 answer:
Firdavs [7]3 years ago
5 0

Answer:

The First Law of Thermodynamics relates internal energy or thermal energy, heat and work. There are some important things to consider. The first law will not tell you the amount of internal or thermal energy, but only how much it has changed. Heat is not temperature. Heat is the flow of energy from hot to cold objects. If heat flows into a system, we consider it positive. If heat flows out of a system, we consider it negative. Work can be done on or by the gas. If the volume increases, the gas is doing the work and we consider this negative. If work is done on the gas, the volume decreases and we consider this positive.

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If argon could exist as a solid, what would best represent the speed through solid argon?
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A 2 kg toy car moves at a speed of 5 m/s.<br> What is the kinetic energy of the car?
ANTONII [103]

Answer:

<h2>The answer is 25 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

KE =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

KE =  \frac{1}{2}  \times 2 \times  {5}^{2}  \\  = 1 \times  {5}^{2}

We have the final answer as

<h3>25 J</h3>

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2 years ago
Z. A force that gives a 8-kg objet an acceleration of 1.6 m/s^2 would give a 2-kg object an
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Answer:

\boxed {\boxed {\sf D.\ 6.4\ m/s^2}}

Explanation:

We need to find the acceleration of the 2 kilogram object. Let's complete this in 2 steps.

<h3>1. Force of 1st Object </h3>

First, we can find the force of the first, 8 kilogram object.

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

F=m \times a

The mass of the object is 8 kilograms and the acceleration is 1.6 meters per square second.

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Substitute these values into the formula.

F= 8 \ kg * 1.6 \ m/s^2

Multiply.

F= 12.8 \ kg*m/s^2

<h3>2. Acceleration of the 2nd Object </h3>

Now,  use the force we just calculated to complete the second part of the problem. We use the same formula:

F= m \times a

This time, we know the force is 12.8 kilograms meters per square second and the mass is 2 kilograms.

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Substitute the values into the formula.

12.8 \ kg*m/s^2= 2 \ kg *a

Since we are solving for the acceleration, we must isolate the variable (a). It is being multiplied by 2 kg. The inverse of multiplication is division. Divide both sides of the equation by 2 kg.

\frac {12.8 \ kg*m/s^2}{2 \ kg}= \frac{2\ kg* a}{2 \ kg}

\frac {12.8 \ kg*m/s^2}{2 \ kg}=a

The units of kilograms cancel.

\frac {12.8}{2}\ m/s^2=a

6.4 \ m/s^2=a

The acceleration is 6.4 meters per square second.

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