KE=1/2 m v^2
KE= .5 x 2kg x 15m/s to the 2nd power
KE=225 km/s
The correct option is (D) Gamma (

)
Explanation:Now this question is a tricky one because all of these options are somehow involved in radioactive decay; however, in this case the SYMBOL is required NOT the elements. There are three symbols involved in radioactive decay, which are:
1. α for alpha decay
2. β for beta decay
3. γ for gamma decay
In the options only one symbol is present which is
gamma. Hence option (D) Gamma ( 
) is the correct answer.
-i
Answer:
nice question but I don't know please forgive me
Answer:
549.9 ohms, 65.65 watts, the power went up
Explanation: power P = V²/R
v= 190volts , P =62watts
from P =V²/R
62=190²/R
making R the subject
R×62= 190²
62R =36100
R=36100/62
R=586.25 ohms
Resistance of each lamp = 586.26/18 =32.3ohms
a) resistance of the light string now = 17×32.3 = 549.9 ohms
b) P=V²/R
where R=549.9ohms , P=?
P=190²/549.9
P=36100/549.9
P=65.65watts
Power dissipated has increased( went up )