Answer:
d. 2.3 ohms (5.3 amperes)
Explanation:
The calculator's 1/x key makes it convenient to calculate parallel resistance.
Req = 1/(1/4 +1/8 +1/16) = 1/(7/16) = 16/7 ≈ 2.3 ohms
This corresponds to answer choice D.
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<em>Additional comment</em>
This problem statement does not tell the applied voltage. The answer choices suggest that it is 12 V. If so, the current is 12/(16/7) = 21/4 = 5.25 amperes.
Answer:
![\triangle V_0=0.08V](https://tex.z-dn.net/?f=%5Ctriangle%20V_0%3D0.08V)
Explanation:
From the question we are told that:
Incremental resistance ![R=8ohms](https://tex.z-dn.net/?f=R%3D8ohms)
Resistor Feed ![R_f=82ohms](https://tex.z-dn.net/?f=R_f%3D82ohms)
Supply Change ![\triangle V=1](https://tex.z-dn.net/?f=%5Ctriangle%20V%3D1)
Generally the equation for voltage rate of change is mathematically given by
![\frac{dV_0}{dV}=\frca{R}{R_1r_3}](https://tex.z-dn.net/?f=%5Cfrac%7BdV_0%7D%7BdV%7D%3D%5Cfrca%7BR%7D%7BR_1r_3%7D)
Therefore
![\triangle V_0=\triangle V*\frac{R}{R_fR}](https://tex.z-dn.net/?f=%5Ctriangle%20V_0%3D%5Ctriangle%20V%2A%5Cfrac%7BR%7D%7BR_fR%7D)
![\triangle V_0=1*\frac{8}{8*82}](https://tex.z-dn.net/?f=%5Ctriangle%20V_0%3D1%2A%5Cfrac%7B8%7D%7B8%2A82%7D)
![\triangle V_0=0.08V](https://tex.z-dn.net/?f=%5Ctriangle%20V_0%3D0.08V)
Answer:
8.85 Ω
Explanation:
Resistance of a wire is:
R = ρL/A
where ρ is resistivity of the material,
L is the length of the wire,
and A is the cross sectional area.
For a round wire, A = πr² = ¼πd².
For aluminum, ρ is 2.65×10⁻⁸ Ωm, or 8.69×10⁻⁸ Ωft.
Given L = 500 ft and d = 0.03 in = 0.0025 ft:
R = (8.69×10⁻⁸ Ωft) (500 ft) / (¼π (0.0025 ft)²)
R = 8.85 Ω
Answer:
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The response to whether the statements made by both technicians are correct is that;
D: Neither Technician A nor Technician B are correct.
<h3>Radio Antennas</h3>
In radios, antennas are the means by which signals to the sought frequency be it AM or FM are received.
Now, if the antenna is bad, it means it cannot pick any radio frequency at all and so Technician A is wrong.
Now, most commercial antennas usually come around a resistance of 60 ohms and so it is not required for a good antenna to have as much as 500 ohms resistance and so Technician B is wrong.
Read more about Antennas at; brainly.com/question/25789224