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3 years ago

a 2000-kilogram car uses a breaking force of 12000 newton’s to stop in 5 seconds. what impulse acts on the car?

Physics

1 answer:

liraira [26]3 years ago

5 0

i honestly don't even know but yahoo answers says :

Impulse causes momentum to change, which means:

Impulse = change in momentum, or in equation form:

F∆t = (mv)2 – (mv)1

so p (impulse)= mass times velocity so the mass is 2,000kg and the velocity is 12,000N/5s.

speed is basically velocity so you have to calculate how many newtons per one second, so 12,000/5s-- just divide the numerator and denominator by 5. Also, velocity and speed are measured in N/s.

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3 years ago

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A 4 kg car with frictionless wheels is on a ramp that makes a 25° angle with the horizontal. The car is connected to a 1 kg mass

stellarik [79]

Refer to the diagram shown below.

W₁ = (4 kg)*(9.8 m/s²) = 39.2 N
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The normal reaction on the 4-kg mass is
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F = (39.2 N)*sin(25°) = 16.5666 N

The net force that accelerates the 4-kg mass at a m/²s down the plane is
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4 years ago

If the distance between two masses is tripled, the gravitational force between changes by a factor of

maw [93]

A. 1/9

Explanation:

The gravitational force between two objects is given by

$F=G\frac{m_1 m_2}{r^2}$

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G is the gravitational constant

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r is the distance between the two masses

From the formula, we see that the magnitude of the force is inversely proportional to the square of the distance: therefore, if the distance is tripled (increased by a factor 3), the magnitude of the force changes by a factor

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3 years ago

Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars

zhuklara [117]

Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.

The distance of the earth from the sun is $1.50 \times 10^{11}\;\rm m$ .

<h3>What is Kepler's third law?</h3>

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

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Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.

By using Kepler's third law, this can be written as,

$T^2 \propto R^3$

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Substituting the values, we get the value of constant k for mars.

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The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.

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Hence we can conclude that the distance of the earth from the sun is $1.50 \times 10^{11}\;\rm m$ .

To know more about Kepler's third law, follow the link given below.

brainly.com/question/7783290.

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