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Yuki888 [10]
3 years ago
7

The small piston in a hydraulic system has a cross-sectional area of 0.5 m2, and the large piston has an area of 3m3. What is th

e force exerted by the large piston if a force of 500 N is exerted on the small piston?
Physics
1 answer:
katrin [286]3 years ago
6 0
     Considering the fluid as ideal, the pressure will spread throughout its volume. Thus,

\frac{F_1}{A_1}=  \frac{F_2}{A_2} \\ F_2= \frac{3\times 500}{0.5}  \\ \boxed {F_2=3000N}

If you notice any mistake in my english, please let me know, because my english level is still low.
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You see a total eclipse of the sun. Three Saros cycles later, you find yourself at the same location.
alukav5142 [94]

Answer:

The correct answer is B. You would not have to travel far to see another total eclipse  .

Explanation:

it is said that the way to predict or know beforehand if there is a lunar or solar eclipse is just to know the what is called the saros which are periods of exactly 223 synodic months and the eclipses are repeated or occurred in the same location every 3 Saros cycles.

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3 years ago
What is electrical conductivity?
Luda [366]

Answer:

Electrical resistivity and its inverse, electrical conductivity, is a fundamental property of a material that quantifies how strongly it resists or conducts electric current. A low resistivity indicates a material that readily allows electric current. Resistivity is commonly represented by the Greek letter ρ.

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3 years ago
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If two planets orbit a star, but planet B is twice as far from the star as planet A, planet A will receive ____ times the flux t
Tresset [83]

Answer:

The nearest plant (A) receives 4 times more radiation from the farthest plant

Explanation:

The energy emitted by the star is distributed on the surface of a sphere, whereby intensity received is the power emitted between the area of ​​the sphere

                I = P / A

               P = I A

The area of ​​the sphere is

               A = 4π r²

Since the amount of radiation emitted by the star is constant, we can write this expression for the position of the two planets

               P = I₁ A₁ = I₂ A₂

               I₁ / I₂ = A₂ / A₁

 Suppose index 1 corresponds to the nearest planet,

            r2 = 2 r₁

            I₁ / I₂ = r₁² / r₂²

            I₁ / I₂ = r₁² / (2r₁)²

            I₁ / I₂ = ¼

           4 I₁ = I₂

The nearest plant (A) receives 4 times more radiation from the farthest plant

7 0
3 years ago
Planets are not uniform inside. Normally, they are densest at the center and have decreasing density outward toward the surface.
SSSSS [86.1K]

Answer:

a = 9.94 m/s²

Explanation:

given,

density at center= 1.6 x 10⁴ kg/m³

density at the surface = 2100 Kg/m³

volume mass density as function of distance

\rho(r) = ar^2 - br^3

r is the radius of the spherical shell

dr is the thickness

volume of shell

dV = 4 \pi r^2 dr

mass of shell

dM = \rho(r)dV

\rho = \rho_0 - br

now,

dM = (\rho_0 - br)(4 \pi r^2)dr

integrating both side

M = \int_0^{R} (\rho_0 - br)(4 \pi r^2)dr

M = \dfrac{4\pi}{3}R^3\rho_0 - \pi R^4(\dfrac{\rho_0-\rho}{R})

M = \pi R^3(\dfrac{\rho_0}{3}+\rho)

we know,

a = \dfrac{GM}{R^2}

a = \dfrac{G( \pi R^3(\dfrac{\rho_0}{3}+\rho))}{R^2}

a =\pi RG(\dfrac{\rho_0}{3}+\rho)

a =\pi (6.674\times 10^{-11}\times 6.38 \times 10^6)(\dfrac{1.60\times 10^4}{3}+2.1\times 10^3)

a = 9.94 m/s²

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Judge a source's reliability 
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