Question

The small piston in a hydraulic system has a cross-sectional area of 0.5 m2, and the large piston has an area of 3m3. What is the force exerted by the large piston if a force of 500 N is exerted on the small piston?

Answer 1

     Considering the fluid as ideal, the pressure will spread throughout its volume. Thus,

$\frac{F_1}{A_1}= \frac{F_2}{A_2} \\ F_2= \frac{3\times 500}{0.5} \\ \boxed {F_2=3000N}$

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