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Semenov [28]
3 years ago
8

two idential train engines are parked on parallel track. one engine has ten cars attached and the other has no cars attached. ea

ch engine exerts the same net force. which allow sthe train to overcome static friction. which engine will be able to accelerate more
Physics
1 answer:
nikklg [1K]3 years ago
6 0

Answer:

The second engine with no cars will accelerate more.

Explanation:

Since the engines are identical so they hacve the same mass. The first engine has 10 cars attached which adds more mass to it whereas second engine has no cars attached.

Therefore second engine is lighter in mass than the first one.

<u>We know from the Newton's second law of motion:</u>

F=m.a

\therefore a=\frac{F}{m}

Now, according to question both the engines exert same force for moving.

We see that :

a\propto\frac{1}{m}

So more is the mass, lesser is the acceleration, hence the second engine with no cars will accelerate more.

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Same thing
6 0
3 years ago
Please help homework due tomorrow,,,
Ad libitum [116K]
Cody ...

Everything on this page is solved with the SAME formula !

             Distance = (speed) x (time) .


Before I get into how to solve each problem, we need to notice that
this whole sheet deals with speed, NOT velocity.

'Velocity' is speed AND THE DIRECTION OF THE  MOTION.
Nothing on this page ever mentions direction, so there's no velocity
anywhere on the page.

Your teacher may not be happy if you talk about this on your homework,
but that's too bad.  Just don't say "velocity" in any of your answers.
Say "speed", and if the teacher complains about that, then it's time to
let the teacher have it with both barrels.
 

1).  Speed = (distance covered) / (time to cover the distance)

2).  Speed = (distance covered) / (time to cover the distance)

3).  Distance  =  (average speed of travel) x (time traveling at that speed)

4).  Time to cover the distance = (distance) / (speed)

5).  Car's     speed = (distance the car covered)        / (time the car took)
      Sprinter speed = (distance the sprinter covered) / (time the sprinter took)

      Calculate the car's speed.
      Calculate the sprinter's speed.
     
      ... Look at the two speeds.
          Decide which one is faster.
     
      ... Subtract the slower one from the faster one. 
          The difference is the answer to "by how much?" .

6).  Distance  =  (speed) x (time spent moving at that speed)

7).  Average speed  =  (TOTAL distance covered)
                                      divided by
                                    (time to cover the TOTAL distance).
   

8 0
3 years ago
Someone please help me will give BRAILIEST!!!!!
Alex777 [14]
Uranium is the right answer. Scientists use 5 percent of the uranium after the bomb is refused to create stronger and better nuclear bombs.
6 0
3 years ago
Compare these two collisions of a PE student with a wall.
Stolb23 [73]

1) The variable that is different in the two cases is \Delta t, the duration of the collision

2) The change in momentum is the same in the two cases

3) The impulse is the same in the two cases

4) Case B will experience a greater force

Explanation:

1)

The variable that is different in the two cases is \Delta t, the duration of the collision.

In fact, in the first case the wall is padded: this means that the collision will be "softer" and therefore will last longer, so the duration of the collision, \Delta t, will be larger.

In the second case instead, the wall is unpadded: this means that the collision is "harder" and so it will last less time, therefore the duration of the collision \Delta t will be smaller.

2)

The change in momentum in the two cases is the same.

In fact, the change in momentum is given by:

\Delta p = m(v-u)

where:

m is the mass of the student

u is the initial velocity

v is the final velocity

In both cases, we have:

m = 75 kg

u = 8 m/s

v = 0 (they both comes to rest)

Therefore, the change in momentum is

\Delta p = (75)(0-8)=-600 kg m/s

3)

The impulse in the two cases is the same.

In fact, impulse is defined as the product of force applied, F, and duration of the collision, \Delta t:

J=F \Delta t

However, the force can be rewritten as product of mass (m) and acceleration (a), according to Newton's second law:

F=ma

So the impulse is

J=ma\Delta t

The acceleration can be rewritten as rate of change of velocity:

a=\frac{\Delta v}{\Delta t}

So the impulse becomes

J=m\frac{\Delta v}{\Delta t}\Delta t = m\Delta v

So, the impulse is equal to the change in momentum: and since in the two cases the change in momentum is the same, the impulse is the same as well.

4)

The force in the collision is related to the impulse by

J=F\Delta t

where

J is the impulse

F is the force

\Delta t is the duration of the collision

The equation can be rewritten as

F=\frac{J}{\Delta t}

In the two situations described in the problem (A and B), we already said that the impulse is the same (because the change in momentum is the same). However, in case A (padded wall) the time \Delta t is longer, while in case B (unpadded wall) the time \Delta t is shorter: since the force F is inversely proportional to the duration of the collision, this means that in case B the student will experience a greatest force compared to case A.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

3 0
3 years ago
A 39-cm-long vertical spring has one end fixed on the floor. Placing a 2.2 kg physics textbook on the spring compresses it to a
Inessa05 [86]

Answer:

The spring constant is 215.6 N/m.

Explanation:

Given that,

Distance = 39 cm

Compresses length = 29 cm

Mass = 2.2 kg

We need to calculate the distance

Using formula of distance

x=l-l'

Put the value into the formula

x=39-29=10\ cm

We need to calculate the spring constant

Using formula of restoring force

F=kx

k=\dfrac{mg}{x}

Where, F = force

x = distance

Put the value into the formula

k=\dfrac{2.2\times9.8}{10\times10^{-2}}

k=215.6\ N/m

Hence, The spring constant is 215.6 N/m.

7 0
3 years ago
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