Answer:
d
Explanation:
Generally, it is transported through pipes so I think statement d is incorrect.
Answer:
A leaf needs carbon dioxide and water for photosynthesis. ... For carbon dioxide to enter, the stomata on the surface of the leaf must be open. As you have seen, transpiration draws water from the roots into the leaf mesophyll.
I hope this helps you :)
Answer:
V₂ = 1866.32 mL
Explanation:
Given data:
Initial temperature = 27.8°C (27 + 273.15 K = 300.15 k)
Initial volume = 1500 mL
Final volume = ?
Final temperature = 100.0°C (100.0 + 273.15 K = 373.15 K)
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
1500 mL / 300.15 k = V₂ / 373.15 K
V₂ = 1500 mL× 373.15 K/ 300.15 k
V₂ = 560175 mL. K /300.15 k
V₂ = 1866.32 mL
Answer: 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH
solution to the endpoint
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
![n_1M_1V_1=n_2M_2V_2](https://tex.z-dn.net/?f=n_1M_1V_1%3Dn_2M_2V_2)
where,
are the n-factor, molarity and volume of acid which is ![HNO_3](https://tex.z-dn.net/?f=HNO_3)
are the n-factor, molarity and volume of base which is KOH.
We are given:
![n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.05M\\V_2=25.0mL](https://tex.z-dn.net/?f=n_1%3D1%5C%5CM_1%3D0.5M%5C%5CV_1%3D%3FmL%5C%5Cn_2%3D1%5C%5CM_2%3D0.05M%5C%5CV_2%3D25.0mL)
Putting values in above equation, we get:
![1\times 0.5\times V_1=1\times 0.05\times 25.0\\\\V_1=2.5mL](https://tex.z-dn.net/?f=1%5Ctimes%200.5%5Ctimes%20V_1%3D1%5Ctimes%200.05%5Ctimes%2025.0%5C%5C%5C%5CV_1%3D2.5mL)
Thus 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH
solution to the endpoint