19.2 g of vinegar solution
Explanation:
Here we have the chemical reaction between acetic acid (CH₃COOH) and calcium carbonate (CaCO₃):
2 CH₃COOH + CaCO₃ → (CH₃COO)₂Ca + CO₂ + H₂O
number of moles = mass / molecular weight
number of moles of CaCO₃ = 0.8 / 100 = 0.008 moles
Knowing the chemical reaction, we devise the following reasoning:
if 2 moles of CH₃COOH react with 1 moles of CaCO₃
then X moles of CH₃COOH react with 0.008 moles of CaCO₃
X = (2 × 0.008) / 1 = 0.016 moles of CH₃COOH
mass = number of moles × molecular weight
mass of acetic acid (CH₃COOH) = 0.016 × 60 = 0.96 g
Now to find the volume of vinegar acid (solution of acetic acid) with a concentration of 5% (weight/volume) we use the following reasoning:
if there are 5 g of acetic acid in 100 mL of vinegar solution
then there are 0.96 g of acetic acid in Y mL of vinegar solution
Y = (0.96 × 100) / 5 = 19.2 g of vinegar solution
Learn more about:
weight/volume concentration
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