Two boxes are accelerated to the right on a frictionless horizontal surface. The larger box has a mass of 9 kilograms and the sm
aller box has a mass of 3 kilograms. If a 24-newton horizontal force pulls on the larger box, with what force does the larger box pull on the smaller box?
A)3N B)6N C)8N D)18N E)24N
A)3N B)6N C)8N D)18N E)24N
2 answers:
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Answer:
= 14.88 N
Explanation:
Let's begin by listing out the given variables:
M = 2.7 kg, L = 3 m, m = 1.35 kg, d = 0.6 m,
g = 9.8 m/s²
At equilibrium, the sum of all external torque acting on an object equals zero
τ(net) = 0
Taking moment about we have:
(M + m) g * 0.5L - (L - d) = 0
⇒ = [(M + m) g * 0.5L] ÷ (L - d)
= [(2.7 + 1.35) * 9.8 * 0.5(3)] ÷ (3 - 0.6)
= 59.535 ÷ 2.4
= 24.80625 N ≈ 24.81 N
Weight of bar(W) = M * g = 2.7 * 9.8 = 26.46 N
Weight of monkey(w) = m * g = 1.35 * 9.8 = 13.23 N
Using sum of equilibrium in the vertical direction, we have:
+
= W + w ------- Eqn 1
Substituting T2, W & w into the Eqn 1
+ 24.81 = 26.46 + 13.23
= <u>14.88</u> N
By definition, the mechanical advantage is the relationship that exists between the output force or load lifted and the value of the force applied.
Thus, using the definition, we have that the mechanical advantage is given by:
Therefore, the mechanical advantage of lifting the box by using a pulley is equal to 1.
Answer:
The mechanical advantage in this situation is:
Equal to 1