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elena-s [515]
4 years ago
6

Two boxes are accelerated to the right on a frictionless horizontal surface. The larger box has a mass of 9 kilograms and the sm

aller box has a mass of 3 kilograms. If a 24-newton horizontal force pulls on the larger box, with what force does the larger box pull on the smaller box?
A)3N B)6N C)8N D)18N E)24N

Physics
2 answers:
MrMuchimi4 years ago
7 0

Answer:

I'd say the answer is (E) just because Newton's first law applies here.

kondor19780726 [428]4 years ago
5 0

Answer:

so option B is right

hope this helps youuuuuuu

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The planet Mars has a mass of 6.1 × 1023 kg and radius of 3.4 × 106 m. What is the acceleration of an object in free fall near t
Oksanka [162]

The acceleration due to gravity of Mars is 3.5\ m / s^{2}

<u>Explanation:</u>

As per universal law of gravity, the gravitational force is directly proportional to the product of masses and inversely proportional to the square of the distance between them. But in the present case, the gravity need to be determined between Mars and the object on Mars. Since the mass of Mars is greater than the mass of any object. Thus,

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Here, G is the gravitational constant, R is the radius of Mars and M, m is the mass of Mars and the object respectively..

Also, according to Newton’s second law of motion, the acceleration of any object will be equal to the ratio of force exerted on it to the mass of the object.

So in order to determine the acceleration due to gravity of Mars, divide the gravitational force of Mars by mass of object on the surface of Mars.

   Acceleration\ due\ to\ gravity\ of\ mars =\frac{\text {Gravitational force of Mars}}{m \text { of object }}

  Acceleration\ due\ to\ gravity\ of\ mars =\frac{G M m}{R^{2} \times m}=\frac{G M}{R^{2}}

  \text { Acceleration due to gravity of mars }=\frac{6.67259 \times 10^{-11} \times 6.1 \times 10^{23}}{3.4 \times 3.4 \times 10^{12}}=\frac{40.703 \times 10^{12}}{11.56 \times 10^{12}}

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Copper Cu 63.546 1 51.431%

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Oxygen O 15.9994 3 38.848%

Explanation:

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