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elena-s [515]
4 years ago
6

Two boxes are accelerated to the right on a frictionless horizontal surface. The larger box has a mass of 9 kilograms and the sm

aller box has a mass of 3 kilograms. If a 24-newton horizontal force pulls on the larger box, with what force does the larger box pull on the smaller box?
A)3N B)6N C)8N D)18N E)24N

Physics
2 answers:
MrMuchimi4 years ago
7 0

Answer:

I'd say the answer is (E) just because Newton's first law applies here.

kondor19780726 [428]4 years ago
5 0

Answer:

so option B is right

hope this helps youuuuuuu

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A solenoid is created by wrapping a L = 85 m long wire around a hollow tube of diameter D = 2.5 cm. The wire diameter is d = 0.7
Dennis_Churaev [7]

the answer is d hope it helps....

5 0
4 years ago
A power lifter performs a dead lift, raising a barbell with a mass of 305 kg to a height of 0.42 m above the ground, giving the
Ann [662]

Answer:

Explanation:

Before it hits the ground:

The initial potential energy = the final potential energy + the kinetic energy

mgH = mgh + 1/2 mv²

gH = gh + 1/2 v²

v = √(2g (H - h))

v = √(2 * 9.81 m/s² * (0.42 m - 0.21 m))

v ≈ 2.0 m/s

When it hits the ground:

Initial potential energy = final kinetic energy

mgH = 1/2 mv²

v = √(2gH)

v = √(2 * 9.81 m/s² * 0.42 m)

v ≈ 2.9 m/s

Using a kinematic equation to check our answer:

v² = v₀² + 2a(x - x₀)

v² = (0 m/s)² + 2(9.8 m/s²)(0.42 m)

v ≈ 2.9 m/s

3 0
3 years ago
To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizontal uniform bar of mass 2.7 kg and length 3.0 m
Zanzabum

Answer:

T_{1} = 14.88 N

Explanation:

Let's begin by listing out the given variables:

M = 2.7 kg, L = 3 m, m = 1.35 kg, d = 0.6 m,

g = 9.8 m/s²

At equilibrium, the sum of all external torque acting on an object equals zero

τ(net) = 0

Taking moment about T_{1} we have:

(M + m) g * 0.5L - T_{2}(L - d) = 0

⇒ T_{2} = [(M + m) g * 0.5L] ÷ (L - d)

T_{2} = [(2.7 + 1.35) * 9.8 * 0.5(3)] ÷ (3 - 0.6)

T_{2}= 59.535 ÷ 2.4

T_{2} = 24.80625 N ≈ 24.81 N

Weight of bar(W) = M * g = 2.7 * 9.8 = 26.46 N

Weight of monkey(w) = m * g = 1.35 * 9.8 = 13.23 N

Using sum of equilibrium in the vertical direction, we have:

T_{1} + T_{2} = W + w   ------- Eqn 1

Substituting T2, W & w into the Eqn 1

T_{1} + 24.81 = 26.46 + 13.23

T_{1} = <u>14.88</u> N

8 0
3 years ago
Relate the output of energy from a heat engine to the energy put into the heat engine considering the second law of thermodynami
Vinil7 [7]

<u>Answer: </u>

<em>Considering the II law of thermodynamics</em>

<em>From the figure</em>

<em>Out put of energy: </em>

Heat supplied from the source/ reservoir  (Q₁) - Heat rejected to the surroundings from the system (Q) = Q₁ - Q₂. Also known as Net work done on the system.

<em>Input of energy: </em>

Amount of heat energy supplied to the system from the source (Q₁ ).

Efficiency (H.E) = η = Output÷ Input

                             η  = (Q₁ - Q₂) ÷ Q₁

                      OR η = Wnet ÷ Q₁ ;        since Wnet = (Q₁ - Q₂)


3 0
3 years ago
Victoria has a crate of vegetables that weighs 100 newtons she exerts a force of 100 Newtons to lift the crate with a pulley wha
miskamm [114]

By definition, the mechanical advantage is the relationship that exists between the output force or load lifted and the value of the force applied.

Thus, using the definition, we have that the mechanical advantage is given by:

MA = \frac{100}{100}\\MA = 1

Therefore, the mechanical advantage of lifting the box by using a pulley is equal to 1.

Answer:

The mechanical advantage in this situation is:

Equal to 1

3 0
4 years ago
Read 2 more answers
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