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3 years ago

12

Because global temperatures are , some species are seeking out elevations in the Himalayas to colonize. Scientists were worried

that these organisms would not have enough to live, but they have found that there is adequate at higher elevations. This movement may help these organisms survive the effects of .

1 answer:

Umnica [9.8K]3 years ago

8 0

Answer:

If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%

Explanation:

If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%If 40 is increased to 56, what is the percent of change?

40%

71%

29%

80%

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A tennis player standing 12.6 m from the net hits the ball at 3.18° above the horizontal. To clear the net, the ball must rise a

SOVA2 [1]

At the vertex, it's vertical velocity is 0, since it has stopped moving up and is about to come back down, and its displacement is 0.33m.
So we use v² = u² + 2as (neat trick I discovered just then for typing the squared sign: hold down alt and type 0178 on ur numpad wtih numlock on!!!) ANYWAY.......
We apply v² = u² + 2as in the y direction only. Ignore x direction.
IN Y DIRECTION:
v² = u² + 2as
0 = u² - 2gh
u = √(2gh) (Sub in values at the very end)
So that will be the velocity in the y direction only. But we're given the angle at which the ball is hit (3° to the horizontal). So to find the velocity (sum of the velocity in x and y direction on impact) we can use: sin 3° = opposite/hypotenuse = (velocity in y direction only) / (velocity)
So rearranging,
velocity = (velocity in y direction only) / sin 3°
= √(2gh)/sin 3°
= (√(2 x 9.8 x 0.33)) / sin 3°
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3 years ago

The empire state building is 1,450 feet tall. King Kong weighs 20 tons and he climbs to the very top. If he jumps off the top, w

lozanna [386]

Answer:velocity= $93.12m/s$

Explanation:

We shall use conservation of energy to solve this problem

we have

Potential energy of King Kong at top of building = His kinetic energy at the bottom

Potential energy of an object = $m\times g\times h$ = 20000 kg

Where m is mass of an object(20000 kg)

g is accleration due to gravity = 9.81 $m/s^{2}$

h is the height above the surface of earth = 1450 feet = 441.96 meters

Applying values we get

$(P.E)_{TOP}=(20000\times 9.81\times 441.96) Joules\\\\(P.E)_{TOP}= 86712.552KiloJoules$ ......................(i)

Now Kinetic energy is given by

$(K.E)_{Bottom}=\frac{1}{2}mv^{2}$ .......................(ii)

Equating i and ii we get

86712.552 = $\frac{1}{2}mv^{2}$

$v=\sqrt{\frac{2E}{m}}$

Applying values we get

$v=\sqrt{\frac{2\times 86712.552\times 10^{3}}{20\times 10^{3}}}\\\\v= 93.12m/s$

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3 years ago

A battery is replaced with one of lower emf. State and explain how the resistance of the lamps would have to change in order to

kow [346]

The brightness of the lamp is proportional to the current flowing through the lamp: the larger the current, the brighter the lamp.

The current flowing through the lamp is given by Ohm's law:

$I=\frac{V}{R}$

where

V is the potential difference across the lamp, which is equal to the emf of the battery, and R is the resistance of the lamp.

The problem says that the battery is replaced with one with lower emf. Looking at the formula, this means that V decreases: if we want to keep the same brightness, we need to keep I constant, therefore we need to decrease R, the resistance of the lamp.

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marin [14]

Answer: Your using your skeletal muscle

Explanation:

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