Question

Find the de Broglie wavelength λ for an electron moving at a speed of 1.00 x 10^6m/s. (Note that this speed is low enough that the classical momentum formula p=mv is still valid.) Recall that the mass of an electron is me=9.11 x 10^−31kg, and Planck's constant is h=6.626 x 10^−34J*s. Express your answer in meters to three significant figures.

Answer 1

Answer:

De broglie wavelength will be 0.727 nm

Explanation:

We have given speed of the electron $v=10^6m/sec$

Mass of the electron $m=9.11\times 10^{-31}kg$

Plank's constant $h=6.624\times 10^{-34}Js$

We have to find the De Broglie wavelength

De Broglie wavelength is given by $\lambda =\frac{h}{mv}=\frac{6.624\times 10^{-34}}{9.11\times 10^{-31}\times 10^6}=0.727\times 10^{-9}m$

So wavelength will be 0.727 nm