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2 years ago

At the maximum height of a projectile’s trajectory—

2 answers:

7 0

Well, a, c, and d are all true, but the simple reason is that the velocity is zero at the top of the flight. The best, simplest answer is 'a'.

uranmaximum [27]2 years ago

5 0

D. Cross product of velocity & amp; acceleration is 0

You might be interested in

A circular wire loop of radius 15.0 cm carries a current of 2.60

Korolek [52]

Part (a): Magnetic dipole moment

Magnetic dipole moment = IA, I = Current, A = Area of the loop
Then,
Magnetic dipole moment = 2.6*π*0.15^2 = 0.184 Am^2

Part (b): Torque acting on the loop
T = IAB SinФ, where B = Magnetic field, Ф = Angle
Then,
T = Magnetic dipole moment*B*SinФ = 0.184*12*Sin 41 = 1.447 Nm

5 0

3 years ago

Why do the waves have different speeds in different layers of Earth's surface?

Genrish500 [490]

Answer:

Material's density

Explanation:

Seismic waves travel at different rates of speed based on a material's density. Hopefully, you understand that the Earth has three main layers: the crust, mantle, and core. Earthquake waves move faster through solids.

6 0

1 year ago

a projectile is launched at an angle of 30 degrees and lands later at the same level. if it's initial speed is 50 m/s, solve for

Mrrafil [7]

$using \: the \: formula \\ t = \frac{2u \sin( \alpha ) }{g} where \: u = initial \: speed \: \\ \alpha = angle \: of \: projection \\ g = acceleration \: due \: to \: gravity \\ \frac{2 \times 50 \times \sin(30) }{10} \\ \frac{100 \times 0.5}{10} = \frac{50}{10} = 5seconds$

Maximum height
= (Usinα)^2/2g
(50*0.5)^2/20
25^2/20
625/20
=31.25metres
horizontal distance = Range= [U^2 * sin2α]/g
[50^2 * sin60]/10
2500 * 0.8660/10
2165/10=216.5metres

3 0

2 years ago

A particle accelerator fires a proton into a region with a magnetic field that points in the x-direction. (a) If the proton is m

iVinArrow [24]

Answer:

The magnitude of the magnetic field will act in a direction towards me.

Explanation:

When a charged particle enters a magnetic field, it is deflected. The direction of travel of the particle is deflected, but the kinetic energy of the particle is not affected. The force experienced by a charged particle as it enters a magnetic field that acts perpendicular to the path of the velocity of the particle, will produce a force that is perpendicular to both the direction of travel of the particle and the direction of the magnetic field. In this case, the proton moves in the y-direction, the magnetic field is in the x-direction, therefore the force experienced by the particle will be towards me.

7 0

3 years ago

A 7.99 g sample of hcn is found to contain 0.296 g of h and 4.14 g of n.Find the mass of carbon in a sample of hcn with a mass o

Thepotemich [5.8K]

Answer:

Mass of C in 3.40 g of HCN =1.51 gram.

Explanation:

Mass of sample of HCN = 7.99 g

Mass of H in 7.99 g of HCN = 0.296 g

Mass of N in 7.99 g of HCN = 4.14 g

Mass of C in 7.99 g of HCN = (7.99-0.296-4.14) = 3.554 g

Now mass of HCN = 3.40 g

Mass of C in 3.40 g of HCN = $\frac{3.554}{7.99} *3.40 =1.51 g$

So mass of C in 3.40 g of HCN =1.51 gram.

3 0

3 years ago