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3 years ago

Which one of the following will change the value of anequilibrium constant?

Chemistry

1 answer:

IRINA_888 [86]3 years ago

6 0

Answer:

d. changing temperature

Explanation:

The thermodynamic equilibrium constant K is defined as a quantity characterizing the equilibrium of a chemical reaction. For a reaction where concentrations are in equilibrium:

aA + bB ⇄ cC + dD

The equilibrium constant is:

$k = \frac{[C]^c[D]^d}{[A]^a[B]^b}$

Thus, the equilibrium constant will change if:

a. Varying the initial concentration of reactants . FALSE. The k constant doesn't depend of initial concentrations but concentration in equilibrium does.

b. Adding other substances that do not react with any of thespecies involved in the equilibrium . FALSE. The equilibrium constant just depends of substances that are involved in the equilibrium

c. Varying the initial concentration of products . FALSE. Again, equilibrium constant doesn't depend of initial concentrations.

d. Changing temperature . TRUE. As a thermodynamic constant, k depends of temperature thus:

$K = e^(-dG/RT)$

e. Changing the volume of the reaction vessel. FALSE. The changing in the volume of the reaction vessel will change just the initial concentrations of the reactants.

I hope it helps!

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3 years ago

To aid in pouring a liquid from wide-mouth container to small mouth container to filter substances when filter paper is used

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The laboratory aid that is used to transfer liquid from a wide-mouth container to a small-mouth container is the funnel. It is shaped like an inverted cone, with an extension of a small tube where the liquid passes. The filter paper is shaped into a cone and inserted to the funnel. The funnel allows you to transfer the liquid without spilling. In filtration, you separate the solid precipitate from the liquid filtrate. It depends on you which one of these you would keep. If you want to keep the filtrate, then the funnel is an efficient way to use if you don't want any of the filtrate to go to waste.

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3 years ago

Physical Science Gas Laws Test

GrogVix [38]

1. A gas occupies 4.31 litres at a pressure of 0.755atm. Determine the volume if the pressure is increased to 1.25 atm.

method: Boyles Law: P1/V1 = P2/V2
P1/V1 = P2/V2 implies V2= P2 V1/ P1
V2=1.25x4.31 / 17=7.13L


2. 600 mL of a gas is at a pressure of 8.00atm. What is the Volume of the gas at 2 atm?

method: Boyles Law: P1/V1 = P2/V2
P1/V1 = P2/V2 implies V2= P2 V1/ P1,
V1=2.6mL=0.026L
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3. How hot will a 2.3 L balloon have to get to expand to a volume of 400 L? Assume that the initial temperature of the balloon is 25 degrees Celsius.

Method: Charles Law: V1/T1 =V2/T2 Degrees Celcius + 273 = Kelvin

25 degrees Celsius=25+273=298K=T1

V1=2.3L, V2=400L

V1/T1 =V2/T2 implies T2=V2T1/V1=(400x298) /2.3=51826 K

4. A gas takes up a volume of 17 litres, has a pressure of 2.3atm, and a temperature of 299K. If I raise the temperature to 350K and lower the pressure to 1.5atm, what is the new volume of the gas?

Combined gas Law: (P1)(V1) = (P2)(V2)
(T1) (T2)

V1=17L
P1=2.3 atm
T1= 299K
P2=1.5 atm
T2=350 K
V2=?

(P1)(V1) / T1= (P2)(V2)/ T2

so V2= (P1)(V1) T2 / P2 T1
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4 years ago

Energy Levels: An ionized atom having Z protons has had all but one of its electrons removed. If E is the total energy of the gr

S_A_V [24]

Explanation:

Formula for energy value is as follows.

E = $\frac{-E_{0}}{n^{2}}$

where, $E_{0}$ = 13.6

n = number of shell

So, at ground state energy of hydrogen atom will be as follows.

E = $\frac{-E_{0}}{n^{2}}$

= $\frac{-13.6}{(1)^{2}}$

= -13.6

Hence, for an ionized atom value of energy will be as follows.

E' = $-13.6 \times Z^{2}$

or, E' = $E \times Z^{2}$

Thus, we can conclude that total energy of the remaining electron in the ionized atom is $E \times Z^{2}$ .

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Answer:

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