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AysviL [449]
3 years ago
11

You observe an unknown substance under a microscope. You notice that the molecules are tightly packed together and not moving. B

ased on this observation, what phase of matter is this substance likely in?
Your answer:

a. Solid

b. Liquid

c. Gas

d. Plasma
Chemistry
1 answer:
enot [183]3 years ago
8 0

Answer:

The answer would be A because they are tightly packed.

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Hellppppp
Margaret [11]

Answer:

c

Explanation:

you don't think of particles as dense and less dense

dust particles containvenergy but won't release it unless acted upon a force

gas molecules move freely and collide with dust particles which is correct

8 0
3 years ago
What is the representative particle for barium chloride?
KIM [24]
Barium chloride is salt with ionic bonds. Barium chloride contains one barium cations (charge of ion is 2+) and two chlorine anions (charge for ion is 1-).
The representative particle<span> of an ionic compound is its formula unit (</span>lowest whole number ratio of ions in an ionic compound), for barium chloride that is BaCl₂.
8 0
3 years ago
Read 2 more answers
one molecule of chlorophyll contains 137 atoms. how many of these atoms come from the metal magnesium?
Svetlanka [38]
The chemical formula for chlorophyll is C55H72O5N4<span>Mg. Only 1 of the 137 atoms comes from magnesium.

</span>
7 0
3 years ago
How does the process of waste removal in a unicellular organism compare to the waste removal in a multicellular organism
Sonja [21]
The digestive system of multicellular is made up of several organs that work together to break down food so that it may be used in the body. Unicellular organisms have organelles, similar to organs, which help to digest food that will be used by the cell
6 0
3 years ago
What volume of CH4(g), measured at 25oC and 745 Torr, must be burned in excess oxygen to release 1.00 x 106 kJ of heat to the su
anastassius [24]

Answer:

V=27992L=28.00m^3

Explanation:

Hello,

In this case, the combustion of methane is shown below:

CH_4+2O_2\rightarrow CO_2+2H_2O

And has a heat of combustion of −890.8 kJ/mol, for which the burnt moles are:

n_{CH_4}=\frac{-1.00x10^6kJ}{-890.8kJ/mol}= 1122.6molCH_4

Whereas is consider the total released heat to the surroundings (negative as it is exiting heat) and the aforementioned heat of combustion. Then, by using the ideal gas equation, we are able to compute the volume at 25 °C (298K) and 745 torr (0.98 atm) that must be measured:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1122.6mol*0.082\frac{atm*L}{mol*K}*298K}{0.98atm}\\\\V=27992L=28.00m^3

Best regards.

8 0
3 years ago
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