Answer:
Oxidative phosphorylation proceeds with the formation of energy laden molecules i.e; carbondioxide and water.
Therefore, Total CO₂ production is directly related to VCO₂ = R x VO₂
where, R is the respiratory quotient varing among 0.7 to 1.0 according to the energy intake (ATP) ie 0.25 of the total diet consumed .
VO₂ is, as mentioned above arterial venous oxygen difference = 6.2ml/dl
therefore, VCO₂ = 0.25 x 6.2
= 1.55 ml/dl
ie; VO₂ : VCO₂ = 6.2 : 1.55.
Explanation:
Answer:
7.146
Explanation:
use the equilibrium equation
7.30 x 10^-7 km. the others have 4 significant figures.
The diameters of the spheres are 72.5 meters square
The mass percent of hydrogen in CH₄O is 12.5%.
<h3>What is the mass percent?</h3>
Mass percent is the mass of the element divided by the mass of the compound or solute.
- Step 1: Calculate the mass of the compound.
mCH₄O = 1 mC + 4 mH + 1 mO = 1 (12.01 amu) + 4 (1.00 amu) + 1 (16.00 amu) = 32.01 amu
- Step 2: Calculate the mass of hydrogen in the compound.
mH in mCH₄O = 4 mH = 4 (1.00 amu) = 4.00 amu
- Step 3: Calculate the mass percent of hydrogen in the compound.
%H = (mH in mCH₄O / mCH₄O) × 100%
%H = 4.00 amu / 32.01 amu × 100% = 12.5%
The mass percent of hydrogen in CH₄O is 12.5%.
Learn more about mass percent here:brainly.com/question/4336659
