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3 years ago

If a helicopter's mass is 4,500kg and the net force on it is 18,000 N upward, what is its acceleration?

Physics

2 answers:

melamori03 [73]3 years ago

5 0

Answer:

Acceleration, $a=4\ m/s^2$

Explanation:

It is given that,

Mass of the helicopter, m = 4500 kg

Net force acting on the helicopter, F = 18000 N

Let a is the acceleration of the helicopter. The force acting on an object is equal to the product of mass and acceleration. It is calculated as :

$F=ma$

$a=\dfrac{F}{m}$

$a=\dfrac{18000\ N}{4500\ kg}$

$a=4\ m/s^2$

So, the acceleration of the helicopter is $4\ m/s^2$ . Hence, this is the required solution.

Vinvika [58]3 years ago

4 0

The acceleration is0.25m/s^2

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Veseljchak [2.6K]

Answer:

$h = 2.821\,m$

Explanation:

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Lastly, the maximum height is determined by using the Principle of Energy Conservation again:

$\frac{1}{2}\cdot (138\,kg)\cdot (5.260\,\frac{m}{s} )^{2} = (138\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot h$

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$h = 2.821\,m$

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4 years ago

what is the magnitude of the gravitational force acting on the earth due to the sun? express your answer in newtons.

Alborosie

The gravitational force the sun experiences from the earth is 3.48×10²²N, which is exactly the same as the force the sun experiences from the earth.

Gravity is a force that develops as a result of the attraction between mass-containing objects. The mass of the object has a direct relationship to the strength of this attraction. r equals the separation of two objects.

F = G (M₁M₂)/r²

Where, F the gravitational force

G=6.67×10⁻¹¹Nm²kg⁻² gravitational constant

M₁=5.98×10²⁴kg mass of earth

M₂= 1.99×10³⁰ kg the mass of the sun

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Putting all the values in above equation,

F = 6.67×10⁻¹¹Nm²kg⁻²(5.98×10²⁴kg 1.99×10³⁰ kg)/15×10¹⁰ m

On solving the above equation we get,

F = 3.48×10²²N

To know more about gravitational force

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1 year ago

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3 years ago

A box of mass 60 kg is at rest on a horizontal floor that has a static coefficient of friction of 0.6 and a kinetic coefficient

gavmur [86]

Answer:

a) The minimum force required to start moving the box is 352.86 N

b) i) The friction force for the box in motion is 147.025 N

ii) The acceleration of box is 4.21625 m/s²

Explanation:

The parameters of the box at rest and the floor are;

The mass of the box = 60 kg

The static coefficient friction of the floor = 0.6

The kinetic coefficient friction of the floor = 0.25

Frictional force = Normal force × Friction coefficient

For an horizontal floor and the box laying on the floor, we have;

The normal force = The weight of the box = Mass of the box × Acceleration due to gravity, g

The acceleration due to gravity, g = 9.81 m/s²

The weight of the box = 60 × 9.81 = 588.6 N

a) The static coefficient gives the frictional force observed by the box and which must be surpassed to bring about motion

Therefore;

The minimum force required to start moving the box = The static frictional force = Weight of the box × The static coefficient of friction

The minimum force required to start moving the box = 588.1 × 0.6 = 352.86 N

The minimum force required to start moving the box = 352.86 N

b) i) When an horizontal force of 400 N is applied, the applied force is larger than the static friction force, and the box will be in motion with the kinetic coefficient of friction being the source of friction

The friction force for the box in motion = 588.1 × 0.25 = 147.025 N

ii) The force, F with the box is in motion, is given as follows;

F = Mass of box × Acceleration of box, a = Applied force - Kinematic friction force

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Zarrin [17]

Answer:

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Explanation:

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The density of the lines is approximately the intensity of the magnetic field.

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3 years ago