Answer:
![\boxed {\boxed {\sf 0.078 \ L }}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%200.078%20%5C%20L%20%7D%7D)
Explanation:
We are asked to find the volume of a solution given the moles of solute and molarity.
Molarity is a measure of concentration in moles per liter. It is calculated using the following formula:
![molarity= \frac{moles \ of \ solute}{liters \ of \ solution}](https://tex.z-dn.net/?f=molarity%3D%20%5Cfrac%7Bmoles%20%5C%20of%20%5C%20solute%7D%7Bliters%20%5C%20of%20%5C%20solution%7D)
We know there are 0.14 moles of potassium chloride (KCl), which is the solute. The molarity of the solution is 1.8 molar or 1.8 moles of potassium chloride per liter.
- moles of solute = 0.14 mol KCl
- molarity= 1.8 mol KCl/ L
- liters of solution=x
Substitute these values/variables into the formula.
![1.8 \ mol \ KCl/ L = \frac { 0.14 \ mol \ KCl}{x}](https://tex.z-dn.net/?f=1.8%20%5C%20mol%20%5C%20KCl%2F%20L%20%3D%20%5Cfrac%20%7B%200.14%20%5C%20mol%20%5C%20KCl%7D%7Bx%7D)
We are solving for x, so we must isolate the variable. First, cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.
![\frac {1.8 \ mol \ KCl/L}{1} = \frac{0.14 \ mol \ KCl}{x}](https://tex.z-dn.net/?f=%5Cfrac%20%7B1.8%20%5C%20mol%20%5C%20KCl%2FL%7D%7B1%7D%20%3D%20%5Cfrac%7B0.14%20%5C%20mol%20%5C%20KCl%7D%7Bx%7D)
![1.8 \ mol \ KCl/ L *x = 1*0.14 \ mol \ KCl](https://tex.z-dn.net/?f=1.8%20%5C%20mol%20%5C%20KCl%2F%20L%20%2Ax%20%3D%201%2A0.14%20%5C%20mol%20%5C%20KCl)
![1.8 \ mol \ KCl/ L *x = 0.14 \ mol \ KCl](https://tex.z-dn.net/?f=1.8%20%5C%20mol%20%5C%20KCl%2F%20L%20%2Ax%20%3D%200.14%20%5C%20mol%20%5C%20KCl)
Now x is being multiplied by 1.8 moles of potassium chloride per liter. The inverse operation of multiplication is division, so we divide both sides by 1.8 mol KCl/L.
![\frac {1.8 \ mol \ KCl/ L *x}{1.8 \ mol \ KCl/L} = \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}](https://tex.z-dn.net/?f=%5Cfrac%20%7B1.8%20%5C%20mol%20%5C%20KCl%2F%20L%20%2Ax%7D%7B1.8%20%5C%20mol%20%5C%20KCl%2FL%7D%20%3D%20%5Cfrac%7B0.14%20%5C%20mol%20%5C%20KCl%7D%7B1.8%20%5C%20mol%20%5C%20KCl%2FL%7D)
![x= \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B0.14%20%5C%20mol%20%5C%20KCl%7D%7B1.8%20%5C%20mol%20%5C%20KCl%2FL%7D)
The units of moles of potassium chloride cancel.
![x= \frac{0.14 }{1.8 L}](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B0.14%20%7D%7B1.8%20L%7D)
![x=0.07777777778 \ L](https://tex.z-dn.net/?f=x%3D0.07777777778%20%5C%20L)
The original measurements of moles and molarity have 2 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 7 in the ten-thousandth place tells us to round the 7 up to a 8.
![x \approx 0.078 \ L](https://tex.z-dn.net/?f=x%20%5Capprox%200.078%20%5C%20L)
There are approximately <u>0.078 liters of solution.</u>
Answer:
See detailed answer with explanation below.
Explanation:
Valence electrons are electrons found on the outermost shell of an atom. They are the electrons in an atom that participate in chemical combination. Recall that the outermost shell of an atom is also referred to as its valence shell. Let us consider an example; if we look at the atom, sodium-11, its electronic configuration is 2,8,1. The last one electron is the valence electron of sodium which is found in its outermost or valence shell.
Positive ions are formed when electrons are lost from the valence shell of an atom. For instance, if the outermost electron in sodium is lost, we now form the sodium ion Na^+ which is a positive ion. Positive ions possess less number of electrons compared to their corresponding atoms.
Negative ions are formed when one or more electrons is added to the valence shell of an atom. A negative ion possesses more electrons than its corresponding atom. For example, chlorine(Cl) contains 17 electrons but the chloride ion (Cl^-) contains 18 electrons.
In molecular compounds, a bond is formed when two electrons are shared between the bonding atoms. Each bonding atom may contribute one of the shared electrons (ordinary covalent bond) or one of the bonding atoms may provide the both shared electrons (coordinate covalent bond). The shared pair may be located at an equidistant position to the nucleus of both atoms. Similarly, the electron may be drawn closer to the nucleus of one atom than the other (polar covalent bond) depending on the electro negativity of the two bonding atoms.
The electrons are shared in order to complete the octet of each atom by so doing, the both bonding atoms now obey the octet rule. For example, two chlorine atoms may come together to form a covalent bond in which each chlorine atom has an octet of electrons on its outermost shell.
Answer:
It is basically a way of telling you how to solve for different variables in the equation d=m/v
Explanation:
Ca(OH)2(aq) + 2HCl(aq)------> CaCl2(aq) + 2H2O(l) ΔH-?
CaO(s) + 2HCl(aq)-----> CaCl2(aq) + H2O(l), Δ<span>H = -186 kJ
</span>
CaO(s) + H2O(l) -----> Ca(OH)2(s), Δ<span>H = -65.1 kJ
</span>
1) Ca(OH)2 should be reactant, so
CaO(s) + H2O(l) -----> Ca(OH)2(s)
we are going to take as
Ca(OH)2(s)---->CaO(s) + H2O(l), and ΔH = 65.1 kJ
2) Add 2 following equations
Ca(OH)2(s)---->CaO(s) + H2O(l), and ΔH = 65.1 kJ
<span><u>CaO(s) + 2HCl(aq)-----> CaCl2(aq) + H2O(l), and ΔH = -186 kJ</u>
</span>Ca(OH)2(s)+CaO(s) + 2HCl(aq)--->CaO(s) + H2O(l)+CaCl2(aq) + H2O(l)
Ca(OH)2(s)+ 2HCl(aq)---> H2O(l)+CaCl2(aq) + H2O(l)
By addig these 2 equation, we got the equation that we are needed,
so to find enthalpy of the reaction, we need to add enthalpies of reactions we added.
ΔH=65.1 - 186 ≈ -121 kJ