Light travels at a speed of:
The distance between Mercury and Sun is
, so the time it takes is
if we want to convert this into minutes, keeping in mind that 1 min = 60 seconds, we should divide this value by 60:
We know, W = k. q₁q₂/ [1/r₁² - r₂² ]
Here, r₁ = R
r₂ = ∞
Substitute their values,
W = k. q₁q₂/ [1/R - 1/∞]
W = k. q₁q₂/ [1/R]
W = k. q₁q₂/ R
Hope this helps!
OK, this is pretty interesting.
First get out your parameters.
Pressure of gas, P= 1.5×10^5 Pa
Initial volume, V1=0.0002m³
Final volume, V2=0.0006m³
Heat change, ∆H= +32J (it is positive since it was absorbed.)
Now you can solve.
∆U= ∆H—P∆V
∆U=32J—(1.5×10^5×(0.0006—0.0002))
∆U=32J—(1.5×10^5×0.0004)
∆U=32J—(1.5×10^5×4×10^—4)
∆U=32—60
∆U=—28J
That corresponds to option C.
Answer:
D
Explanation:
Stomata take in carbon dioxide (i think they realease oxygen too), Phloem transports the glucose throughout the plant, Xylem transports the water and minerals from the roots. If you want me to explain more I can
I don't think that 4m has anything to do with the problem.
anyway. here.
A___________________B_______C
where A is the point that the train was released.
B is where the wheel started to stick
C is where it stopped
From A to B, v=2.5m/s, it takes 2s to go A to B so t=2
AB= v*t = 2.5 * 2 = 5m
The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m
then BC= AC-AB = 7.7-5 = 2.7m
now consider BC
v^2=u^2+2as
where u is initial speed, in this case is 2.5m/s
v is final speed, train stop at C so final speed=0, so v=0
a is acceleration
s is displacement, which is BC=2.7m
substitute all the number into equation, we have
0^2 = 2.5^2 + 2*a*2.7
0 = 6.25 + 5.4a
a = -6.25/5.4 = -1.157
so acceleration is -1.157m/(s^2)