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4 years ago

A 300 kg car travels at 11 ms. What is the momentum

Physics

1 answer:

sweet-ann [11.9K]4 years ago

5 0

The momentum of a <span>300 kg car traveling at 11 ms is 3300 ms</span>

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Every surface has different ____________________ of friction.

dedylja [7]

Answer:

amounts

Explanation:

every surface has different amounts of friction

hope this helps :) plz brainliest?

3 0

3 years ago

An 80 kg skateboarder moving at 3 m/s pushes off with her back foot to move faster.

Dmitry [639]

Answer:

640 J

Explanation:

ΔKE = ½ mv² − ½ mu²

ΔKE = ½ m (v² − u²)

ΔKE = ½ (80 kg) ((5 m/s)² − (3 m/s)²)

ΔKE = 640 J

Work = ΔE

Work = 640 J

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3 years ago

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While at a party, you pull up a sound intensity level app on your phone (everyone does stuff like that, right?), and it reads 83

allochka39001 [22]

To solve this problem it is necessary to apply the concepts related to Sound Intensity. The unit most used in the logarithmic scale is the decibel and mathematically this is expressed as

$\beta_{dB} = 10log_{10}\frac{I}{I_0}$

Where,

$\beta_{dB}$ = Sound intensity level in decibels

I = Acoustic intensity on the linear scale

$I_0 =$ Hearing threshold

According to the values, the total intensity is 32 times the linear intensity and the value in decibels is 83dB

So:

$10log_{10}(\frac{32I}{I_0}) = 83$

$10log(\frac{I}{I_0})+10log(32) = 83$

$10log(\frac{I}{I_0})= 83-10log(32)$

$10log(\frac{I}{I_0})= 67.948dB$

Therefore the sound intensity due to one person is 67.948dB

8 0

3 years ago

The diagram shows a wave. The quantity shown is the amplitude. This quantity is directly proportional to which of these other qu

Katen [24]

As we know that frequency and wavelength are dependent on each other

and this is given by

$f = \frac{c}{\lambda}$

here we know that

$\lambda$ = wavelength

f = frequency

c = speed of wave

while for energy and intensity of wave we know that

Energy = $KA^2$

here A = amplitude of wave

so energy directly depends on amplitude of wave

so correct answer will be

<em>A) Energy</em>

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3 years ago

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What are the fundamental units involved in pascal<br>

Llana [10]

Answer:

<h2>FUNDAMENTAL UNITS INVOLVED ARE : NEWTON AND SECOND .</h2>

<h2>FORMULA OF PRESSURE = </h2>

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3 years ago

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