Answer:
Explanation:
The probability of fi in a range is given by the integral, whose limits are the range limits, of the square of the wave function y(x).
Example:
let's say range [a,b] with wave function y(x), then
One of the characteristics of the luminous gas clouds is that they do not have direct affectation by some type of external electric or magnetic fields.
In addition, we must bear in mind that color is a variable that is depending on the gas in the mixture. Therefore its relationship with spectroscopy allows us to deduce that scientists take advantage of the wavelength spectrum to know the type of composition of one of the clouds. The speed of a cloud is measured by determining the Doppler shift of its spectral lines. From wine's law, wavelength of light emitting from the object depends on temperature of object
Therefore the correct option is D
Answer:
v = 42.92 m/s
Explanation:
Given,
initial speed of the ball, v = 11 m/s
time taken to hit the ground = 5.5 m/s
velocity of the ball just before it hit the ground, v = ?
time taken by the ball to reach the maximum height
using equation of motion
v = u + at
final velocity = 0 m/s
0 = 11 - 9.8 t
t = 1.12 s.
time taken by the ball to reach the water from the maximum height
t' - 5.5 -1.12 = 4.38 s
using equation of motion for the calculation of speed just before it hit the water.
v = u + a t
v = 0 + 9.8 x 4.38
v = 42.92 m/s
Velocity of the ball just before it reaches the water is equal to v = 42.92 m/s
Answer:
d.The wavelength of light and the size of the aperture
Explanation:
<em>The resolution power of an optical system is the smallest distance between two points that the device can distinguish clearly.</em>
It has the following relationship:
where:
r = minimum resolvable distance
n = numerical aperture
= wavelength of the light used for viewing
From above mathematical equation it is clear that:
- Smaller the wavelength better the resolving power
- Larger the aperture better the resolution
(Note, that smaller the value of "r" the more finer details of the image visible through the device.)
