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Mashutka [201]
3 years ago
15

Describe one major infectious in History. Give details.

Physics
2 answers:
777dan777 [17]3 years ago
5 0
El sarampión: más de 200 millones 
El sarampión se caracteriza por causar marcas rojizas en la piel, altas fiebres y malestar general. Además, es también el causante de la segunda mayor pandemia de la historia. La muerte se produce por inflamación pulmonar o de las meninges. Actualmente la mayoría de la población está vacunada contra este mal, ya que entra dentro de la vacuna 'triple viral'. Se contagia mediante contacto directo y por el aire. 
  
<span>Se tienen registros de este virus desde hace más de 3.000 años y, hasta el momento, ha matado a más de 200 millones de personas
</span>
mezya [45]3 years ago
4 0
El sarampión: más de 200 millones 
<span>El sarampión se caracteriza por causar marcas rojizas en la piel, altas fiebres y malestar general. Además, es también el causante de la segunda mayor pandemia de la historia. La muerte se produce por inflamación pulmonar o de las meninges. Actualmente la mayoría de la población está vacunada contra este mal, ya que entra dentro de la vacuna 'triple viral'. Se contagia mediante contacto directo y por el aire. </span>
<span>  </span>
<span>Se tienen registros de este virus desde hace más de 3.000 años y, hasta el momento, ha matado a más de 200 millones de personas

</span>
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An object oscillates with an angular frequency of 8.0 rad/s. At t = 0, the object is at x0 = 4 cm with an initial velocity v0 =
KatRina [158]

Answer:

\phi = 0.66 rad

A = 5.06 cm

Explanation:

We have here a simple harmonic motion, so the equation of the position in this motion is:  

x(t)=Acos(\omega t+\phi) (1)

A: Amplitude

ω: angular frequency

φ: phase constant

If we take the derivative of x with respect to t from (1), we can find the velocity equation of this motion:

v(t)=\frac{dx(t)}{dt}=-A\omega sin(\omega t+\phi) (2)

Let's evaluate (1) and (2) in t=0.

x(0)=Acos(\phi) (3)

v(0)=-A\omega sin(\phi) (4)

Dividing 4 by 3 we have:

\frac{v(0)}{x(0)}=-\omega tan(\phi)

\phi = tan^{-1}(\frac{-v(0)}{\omega x(0)})

\phi = 0.66 rad

Now, using (3) we can find the amplitude.

A = \frac{x(0)}{cos(\phi)} = 5.06 cm

I hope it helps!                            

6 0
4 years ago
15) What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of .35 m?
____ [38]

A pendulum is not a wave.

-- A pendulum doesn't have a 'wavelength'.

-- There's no way to define how many of its "waves" pass a point
every second.

--  Whatever you say is the speed of the pendulum, that speed
can only be true at one or two points in the pendulum's swing,
and it's different everywhere else in the swing.

-- The frequency of a pendulum depends only on the length
of the string from which it hangs.


If you take the given information and try to apply wave motion to it:

             Wave speed = (wavelength) x (frequency)

             Frequency  =  (speed) / (wavelength) ,

you would end up with

             Frequency = (30 meter/sec) / (0.35 meter) = 85.7 Hz

Have you ever seen anything that could be described as
a pendulum, swinging or even wiggling back and forth
85 times every second ? ! ?     That's pretty absurd. 

This math is not applicable to the pendulum.

6 0
3 years ago
An inductive circuit contains resistance of 20 ohm and an inductance of 20 H. If an ac voltage of 120 V and frequency 60 Hz is a
elena-s [515]

Answer:

answer : option (b) 0.016 amp

explanation : resistance of resistor , R = 10 Ω

inductance of inductor , X_LX

L

= 20H

voltage of AC circuit , V = 120volts

frequency, ff =60Hz

so, angular frequency, \omega=2\pi fω=2πf = 2 × π × 60 = 120π rad/s

now, current , i=\frac{V}{\sqrt{R^2+\omega^2L^2}}i=

R

2

+ω

2

L

2

V

= 120/√{10² + (120π)² × 20²}

= 120/√{100 + 14400π² × 400}

after solving this we get, i = 0.016 amp

8 0
3 years ago
Why are the nuclei of the heavier elements radioactive and not the lighter elements of nuclei?
KatRina [158]

Answer:

becouse most of nuclear elements are heave

Explanation:

6 0
3 years ago
PHYSICS 50 POINTS PLEASE HELP
tangare [24]

Answer:

One way to look at Newton’s three laws of motion is this:

The third law states what forces are. That is, all forces are interactions between two different objects. If one object is interacting with another, then equal and opposite forces act on each object. So no force acts alone. When you exert a force on something, it is exerting the identical force back on you.

The first and second laws deal with the consequences of the forces that act on an object. The first law says that in the absence of a net force on an object, it simply continues doing whatever it was already doing. If it is at rest, it will remain at rest. If it is in motion, it will continue with that same motion - at constant speed and in the direction it was already traveling.

The second law says what happens if there is a net force on the object. In that case, the object accelerates - either by changing its speed, its direction, or both - in proportion and in the direction of the net force that acts on it. The amount of acceleration depends the object’s mass. That is, the larger the mass the smaller the acceleration for a given net force. The first and second laws can be summarized in the mathematical expression

F = ma

where F is the vector sum of all the forces that act on the object at any given moment (i.e., the net force), m is the mass of the object, and a is the acceleration of the object due to the net force at that moment - and is always in the same direction of the net force.

And notice that in a way, the first law is then “contained” within the second. That is, if the net force is zero on an object, then so is the acceleration. That is, either the object is (still) at rest or, if already in motion, the velocity didn’t change, in either case, the acceleration was zero.

Explanation:

4 0
3 years ago
Read 2 more answers
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