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3 years ago

Describe one major infectious in History. Give details.

2 answers:

5 0

El sarampión: más de 200 millones
El sarampión se caracteriza por causar marcas rojizas en la piel, altas fiebres y malestar general. Además, es también el causante de la segunda mayor pandemia de la historia. La muerte se produce por inflamación pulmonar o de las meninges. Actualmente la mayoría de la población está vacunada contra este mal, ya que entra dentro de la vacuna 'triple viral'. Se contagia mediante contacto directo y por el aire.

Se tienen registros de este virus desde hace más de 3.000 años y, hasta el momento, ha matado a más de 200 millones de personas

mezya [45]3 years ago

4 0

El sarampión: más de 200 millones
El sarampión se caracteriza por causar marcas rojizas en la piel, altas fiebres y malestar general. Además, es también el causante de la segunda mayor pandemia de la historia. La muerte se produce por inflamación pulmonar o de las meninges. Actualmente la mayoría de la población está vacunada contra este mal, ya que entra dentro de la vacuna 'triple viral'. Se contagia mediante contacto directo y por el aire. 
 
Se tienen registros de este virus desde hace más de 3.000 años y, hasta el momento, ha matado a más de 200 millones de personas

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A parallel-plate vacuum capacitor has 8.60 J of energy stored in it. The separation between the plates is 3.80 mm . If the separ

creativ13 [48]

Answer:

Part a)

$E = \frac{8.60}{2.62} = 3.28 J$

Part b)

$E = 2.62(8.60) = 22.5 J$

Explanation:

As we know that the energy of capacitor when it is not connected to potential source is given as

$U = \frac{Q^2}{2C}$

As we know that initial energy is given as

$8.60 = \frac{Q^2}{2C}$

now we know that capacitance of parallel plate capacitor is given as

$C = \frac{\epsilon_0A}{d}$

now the new capacitance when distance is changed from 3.80 mm to 1.45 mm

$C' = \frac{Cd}{d'}$

$C' = \frac{C(3.80)}{1.45}$

$C' = 2.62 C$

Now the new energy of the capacitor is given as

$E = \frac{Q^2}{2(2.62C)}$

$E = \frac{8.60}{2.62} = 3.28 J$

Part b)

Now if the voltage difference between the plates of capacitor is given constant

now the energy energy of capacitor is

$U = \frac{1}{2}CV^2$

$8.60 = \frac{1}{2}CV^2$

now when capacitance is changed to new value then new energy is given as

$E = \frac{1}{2}C'V^2$

$E = \frac{1}{2}(2.62C)V^2$

$E = 2.62(8.60) = 22.5 J$

6 0

3 years ago

Please help me . i need to answer it asap thankyou

alex41 [277]

The amount of heat needed to melt the block of lead is $5.4\cdot 10^4 J$

Explanation:

The amount of heat needed to melt a solid substance already at its melting point is given by the equation

$Q=m \lambda_f$

where

m is the mass of the substance

$\lambda_f$ is the specific latent heat of fusion

In this problem, we have a block of lead already at its melting point, $327^{\circ}C$ . Its mass is

m = 200 g = 0.2 kg

and its specific latent heat of fusion is

$\lambda_f = 2.7\cdot 10^5 J/kg$

Therefore, the amount of heat needed for the block to completely melt is

$Q=(0.2)(2.7\cdot 10^5)=5.4\cdot 10^4 J$

Learn more about specific heat:

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8 0

3 years ago

A crane lift a cargo 10 m off the ground. If the the crane lifts the cargo box twice as high the potential energy will increase

katrin2010 [14]

Answer:

Two times

Explanation:

The crane lifts the cargo twice as high so the potential energy will increase twice the amount.

4 0

3 years ago

Read 2 more answers

ccording to the law of inertia, if you see an object in motion slowing down, what can you conclude? a. That there must be some e

ivanzaharov [21]

Answer:

Explanation:

Newton's First law (aka law of inertia) says that any object, not subject to an external influence, must be keep in its present motion status (at rest or moving at constant speed along a straight line) forever.

So, if we see an object in motion slowing down, there must be an external infuence acting on it, that makes it slow down, like a friction force, for instance.

7 0

3 years ago

A car going 50 mph accelerates to pass a truck. Five seconds later the car is

Alex

The vehicle accelerates at 2.648 m/s².

We have:

Initial velocity, u = 50 miles per hour = 22.352 m/s

final velocity, v = 80 miles per hour = 35.762 m/s

Time, t = 5 seconds

The time in hours is:

t = 5 seconds

Now, the acceleration of the car can be calculated using the formula:

v = u + at

35.762 = 22.352 + a(5)

a(5) = 30

a = 2.682 m/s²

From the calculations above, the acceleration of the car is 2.682 m/s².

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3 0

2 years ago