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sesenic [268]
3 years ago
13

Why is the gravitational force usually ignored in problems involving particles such as electrons and protons?

Physics
1 answer:
Studentka2010 [4]3 years ago
4 0

Answer:

Because the mass of electrons and protons is very small

Explanation:

The gravitational force exerted between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

G=6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

m1 and m2 are the masses of the two objects

r is the distance between the two objects

The mass of a proton and of an electron is very small, so the gravitational force involved in case of such particles is very weak. Let's calculate for example the gravitational attraction between one proton and one electron at a distance of r = 1 m. We have:

- Proton mass: m_1 = 1.67 \cdot 10^{-27}kg

- Electron mass: m_2 = 9.11\cdot 10^{-31}kg

So, the gravitational force between the two particles is:

F=(6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2})\frac{(1.67\cdot 10^{-27}kg)(9.11\cdot 10^{-31} kg)}{(1 m)^2}=1.01\cdot 10^{-67}N

Which is a very weak force.

By comparison, let's calculate instead the electromagnetic force between a proton and an electron (both having a charge of q=1.6\cdot 10^{-19}C) still separated by a distance of r = 1 m. We have:

F=k\frac{q_1 q_2}{r^2}=(9.0\cdot 10^9 Nm^2C^{-2})\frac{(1.6\cdot 10^{-19}C)(1.6\cdot 10^{-19}C)}{(1 m)^2}=2.3\cdot 10^{-28}N

Which we see is much stronger than the gravitational force (almost by a factor 10^{40}

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sweet-ann [11.9K]

Answer:

Oxygen-Symbol-O Potassium Symbol-K

6 0
3 years ago
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A driver averaged 64 mph and took 3½ hours to travel from st. Louis to chicago. Based on this, what is the distance between st.
sammy [17]

Average speed of the driver is given as

v = 64 mph

if he moved for total time t = 3.5 hours

so the distance between the tow is given as

d = v* t

d = 64 * 3.5

d = 224 miles

so the distance between St. Louis and Chicago is 224 miles

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3 years ago
A spacecraft is fueled using hydrazine (N2H4; molecular weight of 32 grams per mole [g/mol]) and carries 1640 kilograms [kg] of
Sauron [17]

Answer:

The value is t = 689.029 \  hours

Explanation:

From the question we are told that

The molar mass of hydrazine is Z =  32 g/mol = \frac{32}{1000} = 0.032 \  kg/mol

The initial temperature is T_i  =  -186 ^o F = (-186-32) *\frac{5}{9} +273.15 = 152\ K

The final temperature is T_f  =  78 ^o F = (78-32) *\frac{5}{9} +273.15 = 298.7 \ K

The specific heat capacity is c_h  =  0.099 [kJ/(mol K)] = 0.099 *10^3 J/(mol/K)

The power available is P = 300 \ W

The mass of the fuel is m =   1640 \  kg

Generally the number of moles of hydrazine present is

n  =  \frac{m}{Z}

=> n  =  \frac{1640}{= 0.032}

=> n  =  51250 \ mol

Generally the quantity of heat energy needed is mathematically represented as

Q =  n * c_h * (T_f -T_i)

=> Q =  51250  * 0.099 *10^3  * (298.7 - 152)

=> Q =  7.441516913 * 10^{8} \  J

Generally the time taken is mathematically represented as

t =  \frac{Q}{P}

=> t =  \frac{7.441516913 * 10^{8} }{300}

=> t = 2480505.6377 s

Converting to hours

t = \frac{2480505.6377}{3600}

=> t = 689.029 \  hours

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3 years ago
Which of the below statements are true?
andrezito [222]

Answer:

B

Explanation:

Displacement is the distance from the start point to the endpoint, displacement disregard the path taken or the amount traveled.

if you start at point A, then go to point B, and back to point A, the displacement is zero because you started and ended at the same point.

for this question, pretend you started at point A, went east 20 km to point B, and then west 8 km to point C, your displacement is 12 km. 12 km is the distance between point A and point C.

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What is newton's first low of motion?​
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