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saveliy_v [14]
3 years ago
7

16.1 (a) Briefly explain the difference between oxidation and reduction electrochemical reactions. (b) Which reaction occurs at

the anode and which at the cathode?
Engineering
1 answer:
Talja [164]3 years ago
4 0

Answer:

a)  The one that is loosing electron is oxidation process and the one that is gaining electron is reduction.

b)    Reduction reaction occur at cathode while oxidation reaction occur at Anode.

Explanation:

The main difference between the reduction and oxidation process is based on gaining and loosing of electron.

Reduction and oxidation both occur simultaneously. one is loosing electron and other is gaining.  The one that is loosing electron is oxidation process and the one that is gaining electron is reduction.

B) Reduction reaction occur at cathode while oxidation reaction occur at Anode.

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Half-wave rectifier converts an AC signal into a DC signal. It's called a half-wave because it only rectify the positive part of an AC signal.

AC Signal = An electrical signal that alternates between positive and negative voltage.

DC Signal = An electrical signal that only has positive voltage.

Rectify = A fancy word for converting something.

Adding a capacitor helps the positive part of the signal stay on longer. This work because the capacitor stores energy kinda like a battery. During the negative part of the AC signal, the energy stored in the capacitor will be drained and used, then the cycle repeats.

The load resistor is just there to prevent a short circuit from happening.

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Which of the following team members would not be involved in the design of
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Read 2 more answers
2)Prueba de presión Cuando a una persona se le somete a una prueba de presión, por lo general se le indica que, al llegar el rit
Olin [163]

Usando la ecuación de regresión que modela la frecuencia cardíaca máxima, podemos obtener el valor predicho de los problemas dados así:

La ecuación lineal que modela la frecuencia cardíaca máxima permitida en función de la edad del paciente está relacionada con la fórmula:

  • m = - 0,875x + 190

<em>x = edad del paciente; m = máx. frecuencia cardíaca permitida</em>

1.) <u>Frecuencia cardíaca máxima permitida para una persona de 50 años:</u>

Sustituye x = 50 en la ecuación:

m = -0,875 (50) + 190

m = 146,25

Por lo tanto, la frecuencia cardíaca máxima permitida es de aproximadamente 146 latidos / min.

2.) <u>Edad para una persona con frecuencia cardíaca máxima de 160 latidos / min</u>:

Sustituye m = 160 en la ecuación:

160 = -0,875x + 190

0,875x = 190 - 160

0,875x = 30

x = 30 / 0,875

x = 34,28

Por tanto, la edad de la persona sería de unos 34 años.

Más información: brainly.com/question/25395533

3 0
3 years ago
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