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777dan777 [17]
3 years ago
6

Telnet into a Web server and send a multiline request message. Include in the request message the If-modified-since: header line

to force a response message with the 304 Not Modified status code.

Engineering
1 answer:
KiRa [710]3 years ago
5 0

Answer:

The following command is issued

in Windows command prompt

followed by the HTTP GET

message to the “utopia.poly.edu"

web server:

> telnet utopia.poly.edu 80

As the index.html page in the web

server was not modified since

Mon, 18 May 2015 09:23:34GMT,

the following outputwas displayed

when the above commands were

issued on Sat, 23 May 2015.

The first 4 lines are the GET

message and header lines input by

the user.

The next 4 lines (starting from

HTTP/1.1 304 Not Modified) are

the response from the web server.

Explanation:

File is also attach which might help to explain the answer.

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Gold forms a substitutional solid solution with silver. Calculate the number of gold atoms per cubic centimeter (in atoms/cm3) f
bija089 [108]

Answer:

Na = 5.911 × 10^{21}  atoms/cm³

Explanation:

given data

silver-gold alloy  C Au = 17 wt%

densities ρ Au = 19.32 g/cm³

densities ρ Ag = 10.49 g/cm³

atomic weights A Au  = 196.97 g/mol

atomic weights A Ag  = 107.87 g/mol

solution

we will apply here formula for number of gold atoms that is

Na = \frac{NA * C Au}{\frac{C Au * A Au}{\rho Au} + \frac{A Au * (100-C Au)}{\rho Ag}}        ............................1

here NA is Avogadro's number and ρ  is density of two element and A is atomic weight

put here value

Na = \frac{6.022*10^{23} * 0.17}{\frac{0.17 * 196.97}{19.32} + \frac{196.97 * (100-0.17)}{10.49}}

Na = 5.911 × 10^{21}  atoms/cm³

8 0
4 years ago
Ethylene (C2H4) gas enters a well-insulated reactor and reacts completely with 400% of theoretical air, each at 25°C, 2 atm. The
GuDViN [60]

Answer:see explanation.

Explanation:

(a).The equation of reaction is;

C2H4 + 3(O2 + 3.76N2) -----> 2CO2 + 2H2O + 11.28 N2.

Theoretical air is the amount of air that will allow the complete combustion of the fuel. Air contains 21% of oxygen,79% of Nitrogen. Thus, the molecular mass of air = 29 [Kg/Kmol] . The number of oxygen needed to oxidize the hydrocarbon(C2H4) is 79/21= 3.76 moles of Nitrogen.

(b). N(total) =2+2+11.28 =15.28 kmoles of product

15.28[h(T) - h°] of air

= 15.28(Mass of air) (Cp,1000k)

T(adiabatic) = 802,310 kJ/k. Mole.

When mass of air= 29 Kg/ k.mol

Cp,1000k = 1.142 kJ.k which is the specific heat capacity of air.

T(adiabatic) = 1275k -----> assuming all the products are air.

(C). 2{∆h} co2 + 2{∆h} H20 +11.28 {∆h} N2

After series of calculations and checking of tables:

S(o2) = 320.173 - 8.314 ln 0.12= 337.46 kJ/ K.mol.k

S(H2O)= 273.986- 8.314 ln 0.1406 = 290.30 KJ/ kmol. K

S(N2) = 258.503- 8.314 ln 0.7344= 261.07 kJ/kmol.k

= 2(337.46) + 2(290.30)+11.28(261.07)-360.79-3(218.01)-11.28(193.46)

=1003.3378 kJ/kmol. K

5 0
3 years ago
A steam reformer operating at 650C and 1 atm uses propane as fuel for hydrogen production. At the given operating conditions, th
dusya [7]

Answer:

Explanation:

a) for shifting reactions,

Kps =  ph2 pco2/pcoph20

=[h2] [co2]/[co] [h2o]

h2 + co2 + h2O + co + c3H8 = 1

it implies that

H2 + 0.09 + H2O + 0.08 + 0.05 = 1

solving the system of equation yields

H2 = 0.5308,

H2O = 0.2942

B)  according to Le chatelain's principle for a slightly exothermic reaction, an increase in temperature favors the reverse reaction producing less hydrogen. As a result, concentration of hydrogen in the reformation decreases with an increasing temperature.

c) to calculate the maximum hydrogen yield , both reaction must be complete

C3H8 + 3H2O ⇒ 3CO + 7H2( REFORMING)

CO + H2O ⇒ CO2 + H2 ( SHIFTING)

C3H8 + 6H2O ⇒ 3CO2 + 10 H2 ( OVER ALL)

SO,

Maximum hydrogen yield

= 10mol h2/3 molco2 + 10molh2

= 0.77

⇒ 77%

3 0
3 years ago
What must a new object have in Turtle Graphics?<br><br> Export<br> Name<br> Title<br> Rank
elena55 [62]

Answer:

Title

Explanation:

5 0
3 years ago
Read 2 more answers
Increasing rake angle will decrease the tendency for Built-Up-Edge to form. a) True b) False
anygoal [31]

Answer:

a)True

Explanation:

While machining of ductile material and high feed and low cutting speed welding action take place between tool material and chip material this welding action is called built up edge. Built up edge action takes place due to high temperature.

To decrease the built up edge action

1. Increase the rake angle.

2. Increase the cutting speed

3. Decrease the feed rate

4. Use cutting fluid

7 0
3 years ago
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