Answer:
Explanation:
Given:
- angle of launch of projectile from horizontal,
- range of projectile,
<u>We have formula for the range of projectile:</u>
putting the respective values
is the velocity with which Tom should jump to land on the other roof.
Answer:
3.round object that orbits the Sun but lacks the ability to clear the neighborhood around its orbit.
Explanation:
in 2006 the IAU, said that a dwarf planet is round object that has not cleared the area round a object and that is why Pluto, Ceres, and Eris are dwarf planet.
Adjust the height of the wooden rod so that it just touches the surface of the water. Switch on the lamp and motor and adjust the speed of the motor until low frequency waves can be clearly observed... Count the number of waves passing a point in ten seconds then Divide by ten to record frequency.
Answer: The height above the release point is 2.96 meters.
Explanation:
The acceleration of the ball is the gravitational acceleration in the y axis.
A = (0, -9.8m/s^)
For the velocity we can integrate over time and get:
V(t) = (9.20m/s*cos(69°), -9.8m/s^2*t + 9.20m/s^2*sin(69°))
for the position we can integrate it again over time, but this time we do not have any integration constant because the initial position of the ball will be (0,0)
P(t) = (9.20*cos(69°)*t, -4.9m/s^2*t^2 + 9.20m/s^2*sin(69°)*t)
now, the time at wich the horizontal displacement is 4.22 m will be:
4.22m = 9.20*cos(69°)*t
t = (4.22/ 9.20*cos(69°)) = 1.28s
Now we evaluate the y-position in this time:
h = -4.9m/s^2*(1.28s)^2 + 9.20m/s^2*sin(69°)*1.28s = 2.96m
The height above the release point is 2.96 meters.
Answer:
Velocity(v) = frequency(f) × wavelength
f = 0.3165
Wavelength = 2×length(L)
L = 157cm
Convert the length in centimetres to metre = 1.57m
v = 2×1.57 × 0.3165
v = 0.99m/s
Approx. 1m/s
Explanation:
The velocity of a wave is the product of its frequency and it's wavelength. The frequency is already known. The wavelength is the distance between two successive wave crests which is formed by sloshing water back and forth in the bath tub. Sloshing water to one end of the tub will produce a wave crest first at that end then the other completing a cycle. The wavelength will be twice the length of the bath tub as it is the distance that both crests are formed.
Wave crest is the highest point of a wave, and in this case is where the water rises to a high point in the bath tub
