Answer:
Average atomic mass = 63.553 amu.
Explanation:
Given data:
Abundance of Y-63 = 69.17%
Abundance of Y-65 = 100 - 69.17 = 30.83%
Atomic mass of Y-63 = 62.940 amu
Atomic mass of Y-65 = 64.928 amu
Atomic mass of Y = ?
Solution:
Average atomic mass= (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass= (62.940×69.17)+(64.928×30.83) /100
Average atomic mass = 4353.560 + 2001.730 / 100
Average atomic mass = 6355.29 / 100
Average atomic mass = 63.553 amu.
Answer:
CH2O and C6H12O6
Explanation:
To find an empirical formula, take a molecular formula and divide the subscript of each element by the greatest common factor of all the subscripts. In this case, the only pair that works is CH2O,C6H12O6, which can be verified by dividing the coefficients of the molecular formula by 6.
Some of the symptoms from swallowing hydrochloric acid:
<span><span>
</span></span><span><span>-Abdominal pain
</span>-Breathing difficulty due to swelling of throat
-Chest pain
-Drooling
-Fever
-Mouth pain
-Rapid drop in blood pressure
-Throat pain <span>
-Vomiting blood</span></span>
First, need to know the formula of Molarity.
moles of solute
Molarity = ---------------------------
liters of solution
Given
2.0 liter of solution
58 grams of NaCl
Base of my research the moles of 58 grams of NaCl is 0.750 moles
Solution
0.750 moles
Molarity = ----------------------- = 0.375
2.0 L
The molarity of this solution is 0.375
Answer:
compounds
Explanation:
the actual term would be chemical compound
