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Marysya12 [62]
3 years ago
8

When nh4clo4(s) decomposes thermally, the products of the reaction are n2(g), o2(g), h2o(g), and hcl(g). write the balanced equa

tion (including phases) for this reaction?
Chemistry
1 answer:
worty [1.4K]3 years ago
6 0
When a certain compound is decomposed thermally, it means that the compound is separated into its individual pure elements occurring in nature. In this case, this happens in the presence of heat. The decomposition reaction is:

<span><em>4 NH</em></span><em>₄</em><span><em>ClO</em></span><em>₄</em><span><em> (s) --> 2 N</em></span><em>₂ (g)</em><span><em> + 5 O</em></span><em>₂ (g)</em><span><em> + 6 H</em></span><em>₂</em><span><em>O (g) + 4 HCl (g)</em></span>
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When heated, calcium hydroxide and ammonium chloride react to produce ammonia gas, water vapor, and solid calcium chloride.
NNADVOKAT [17]

Answer:

13.73g

Explanation:

mass of reactants = mass of products.

Mass reactants = 5.00 g + 10.00 g = 15.00 g

Mass products = 1.27g + mass of ammonia and water vapor

Mass of ammonia and water vapor

15.00g – 1.27 g = 13.73 g

3 0
3 years ago
A student knows that hydrogen (H) atoms and oxygen (O) atoms combine to form water (H2O). The student correctly predicts that hy
marusya05 [52]

Answer:

A

Explanation:

They both need to lose 2 electrons to form ions

6 0
3 years ago
What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol
statuscvo [17]

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L    

M = Moles / Liter

.3151 L  x <u>0.5 mol EDTA</u>  x  <u>374 g EDTA</u>  =  58.92 g EDTA

                1 L EDTA             1 mol EDTA

4 0
2 years ago
Titration of a 20.0-mL sample of acid rain required 1.7 mL of 0.0811 M NaOH to reach the end point. If we assume that the acidit
Rasek [7]

Answer:

Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.

Explanation:

Volume of NaOH = 1.7 ml = 0.0017 L

Molarity of NaOH = 0.0811 M

Moles of NaOH = n

0.0811 M=\frac{n}{0.0017 L}

n = 0.0001378 mol

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

According to reaction, 2 mol of NaOH neutralize 1 mol of sulfuric acid.

Then 0.0001378 mol of NaOH will neutralize:

\frac{1}{2}\times 0.0001378 mol=6.8935\times 10^{-5} mol of sulfuric acid.

Concentration of sulfuric acid in the acid rain sample: x

x=\frac{6.8935\times 10^{-5}}{0.02 L}=0.0034467 mol/L

Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.

7 0
3 years ago
The following pairs of aqueous solutions are separated by a semipermeable membrane. In which direction will the solvent flow?a.
raketka [301]

Answer:

osmosis is a process where by solvent or fluid molecules flow from low concentration to high concentration.

So in

A.solvent will flow from B to A because

B = 3.45 M sodium bromide is more concentrated than 3.45 M calcium iodide;

b) solvent still flow from B to A because

A = 5.00 M sucrose is less concentrated than B = 3.00 M potassium nitrate

7 0
3 years ago
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