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Marysya12 [62]
3 years ago
8

When nh4clo4(s) decomposes thermally, the products of the reaction are n2(g), o2(g), h2o(g), and hcl(g). write the balanced equa

tion (including phases) for this reaction?
Chemistry
1 answer:
worty [1.4K]3 years ago
6 0
When a certain compound is decomposed thermally, it means that the compound is separated into its individual pure elements occurring in nature. In this case, this happens in the presence of heat. The decomposition reaction is:

<span><em>4 NH</em></span><em>₄</em><span><em>ClO</em></span><em>₄</em><span><em> (s) --> 2 N</em></span><em>₂ (g)</em><span><em> + 5 O</em></span><em>₂ (g)</em><span><em> + 6 H</em></span><em>₂</em><span><em>O (g) + 4 HCl (g)</em></span>
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Write the beta decay equation for the following isotope: 91 38 Sr? Please write out steps
babymother [125]

Answer:

\rm _{38}^{91}Sr \longrightarrow \,  _{-1}^{0}e + \,  _{39}^{91}Y

Explanation:

The unbalanced nuclear equation is

\rm _{38}^{91}Sr \longrightarrow \,  _{-1}^{0}e \, + \, ?

Let's write the question mark as a nuclear symbol.

\rm _{38}^{91}Se} \longrightarrow \,  _{-1}^{0}e \, + \,  _{Z}^{A}X

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

98 =  0 + A, so A =  98 -  0 = 98, and

38 = -1 + Z, so Z  = 38 + 1 = 39

Then, your nuclear equation becomes

\rm _{38}^{91}Sr \longrightarrow \,  _{-1}^{0}e + \,  _{39}^{91}X

Element 39 is yttrium, so the balanced nuclear equation is

\rm _{38}^{91}Sr \longrightarrow \,  _{-1}^{0}e + \,  _{39}^{91}Y

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madreJ [45]

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3 years ago
The following reaction shows sodium carbonate reacting with calcium hydroxide.
velikii [3]

Ans: 15.1 grams

Given reaction:

Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3

Mass of Na2CO3 = 20.0 g

Molar mass of Na2CO3 = 105.985 g/mol

# moles of Na2CO3 = 20/105.985 = 0.1887 moles

Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH

# moles of NaOH produced = 0.1887*2 = 0.3774 moles

Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol

Mass of NaOH produced = 0.3774*39.996 = 15.09 grams


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