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4 years ago

What is an atomic nucleus?

Physics

2 answers:

Evgesh-ka [11]4 years ago

8 0

Answer:

Explanation:

An atom consists of a central core in which almost entire mass and entire positive charge is concentrated. Around the nucleus, the electrons are revolving around it in fixed orbits.

the protons and the neutrons are residing in the atomic nucleus. they are collectively called as nucleons.

The protons are positively charged and the neutrons are neutral, so the entire positive charge is in the nucleus.

Pavel [41]4 years ago

4 0

The atomic nucleus is made up of a certain amount of protons(+ charge) and neutrons (0 charge). It is the center of an atom. The electrons (- charge) orbit the nucleus.

Hope this answers it.

Brady

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If an ocean wave passes a stationary point every 5 s and has a velocity of 10 m/s, what is the wavelength of the wave

Rainbow [258]

Answer:

As Per Provided Information

Velocity of wave v is 10m/s

These ocean wave passes a stationary point every 5 s ( It's time period)

First we calculate the frequency of ocean wave .

Using Formulae

$\blue{\boxed{\bf \: \nu = \cfrac{1}{v}}}$

here

v is the velocity of wave .

$\sf\longrightarrow \nu \: = \cfrac{1}{10} \\ \\ \\ \sf\longrightarrow \nu \: = 0.1Hz$

Now calculating the wavelength of the wave .

Using Formulae 

$\boxed{ \bf \lambda = \cfrac{v}{ \nu}}$

Substituting the value and we obtain

$\sf \longrightarrow \lambda \: = \cfrac{10}{0.1} \\ \\ \\ \sf \longrightarrow \lambda \: = \cancel\cfrac{10}{0.1} \\ \\ \\ \sf \longrightarrow \lambda \: =100m$

Therefore,

Wavelength of the wave is 100 metres.

8 0

3 years ago

Find the center of mass (in cm) of a one-meter long rod, made of 50 cm of copper (density 8.92 g/cm3) and 50 cm of iron (density

Gennadij [26K]

Answer

given,

copper rod length = 50 cm

density of the copper = 8.92 g/cm³

iron rod length = 50 cm

density of iron = 7.86 g/cm³

mass of iron = density × volume

m_i = 7.86 × A × l/2

m_c = 8.96 × A × l/2

taking the intersection of copper and iron rod be starting point cooper side is taken as positive side and iron side length is taken to be -ve side.

center of mass

= $\dfrac{m_i\times \dfrac{-l}{4}+m_c\times \dfrac{l}{4}}{m_i+m_c}$

= $\dfrac{7.86\times A \times \dfrac{l}{2}\times \dfrac{-l}{4}+8.96\times A \times \dfrac{l}{2}\times \dfrac{l}{4}}{7.86\times A \times \dfrac{l}{2}+8.96\times A \times \dfrac{l}{2}}$