The given question is incomplete. The complete question is as follows.
A 75-g bullet is fired from a rifle having a barrel 0.540 m long. Choose the origin to be at the location where the bullet begins to move. Then the force (in newtons) exerted by the expanding gas on the bullet is 
, where x is in meters. Determine the work done by the gas on the bullet as the bullet travels the length of the barrel.
Explanation:
We will calculate the work done as follows.
W = 
= 
= ![[14000x + 5000x^{2} - 8666.7x^{3}]^{0.54}_{0}](https://tex.z-dn.net/?f=%5B14000x%20%2B%205000x%5E%7B2%7D%20-%208666.7x%5E%7B3%7D%5D%5E%7B0.54%7D_%7B0%7D)
= 7560 + 1458 - 1364.69
= 7653.31 J
or, = 7.65 kJ (as 1 kJ = 1000 J)
Thus, we can conclude that the work done by the gas on the bullet as the bullet travels the length of the barrel is 7.65 kJ.
The answer is c 1386j
This calculator is very helpful I use it on my homework
https://www.omnicalculator.com/physics/specific-heat
Answer:
44 N/m
Explanation:
The extension, e, of the spring = 2.9 m - 1.4 m = 1.5 m
The work needed to stretch a spring by <em>e</em> is given by
where <em>k</em> is spring constant.
Using the appropriate values,
Answer:
The polytropic exponent (n) is 1.2
The amount of energy transfer by work is 552.45 Btu
Explanation:
P1V1^n = P2V2^n
P1 = 75 lbf/in^2 = 75 lbf/in^2 × 143.3 in^2/ft^2 = 10,747.5 lbf/ft^2
V1 = 4 ft^3/lb × 10 lb = 40 ft^3
P2 = 20 lbf/in^2 = 20 × 143.3 = 2866 lbf/ft^2
V2 = 12 ft^3/lb × 10 lb = 120 ft^3
(V2/V1)^n = P1/P2
(120/40)^n = 10747.5/2866
3^n = 3.75
ln 3^n = ln 3.75
n ln 3 = ln 3.75
n = ln 3.75/ln 3 = 1.2
W = (P2V2 - P1V1)/1 - n = (2866×120 - 10747.5×40)/1-1.2 = (343,920 - 429,900)/-0.2 = -85,980/-0.2 = 429,900 lbf.ft = 429,900/778.17 Btu = 552.45 Btu
Answer:
The conservation of energy of energy states that energy can neither be created nor destroyed but can be transferred from one form to other. It also states that energy of bodies remain constant in a closed system.
While striking (light) a match, the mechanical energy is utilized is transformed to thermal energy, this thermal energy then releases the chemical energy stored in match. The chemical energy at the ends transform to thermal energy which is visible as as light.
So, in this the energy transformation that occurs remain constant.
