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Juliette [100K]
4 years ago
13

When a rattlesnake strikes, its head accelerates from rest to a speed of 32 m/s in 0.63 seconds. Assume for simplicity that the

only moving part of the snake is its head of mass 200 g. How much (average) power does the rattlesnake need to accelerate its head that fast?
Physics
1 answer:
irina [24]4 years ago
4 0

Answer:

Power, P = 162.53 Watts          

Explanation:

Given that,

Mass, m = 200 g = 0.2 kg

Initial speed of the snake, u = 0

Final speed of the snake, v = 32 m/s

Time, t = 0.63 s

Power of an object is given by :

P=\dfrac{W}{t}

P=\dfrac{\Delta K}{t}

P=\dfrac{mv^2}{2t}

P=\dfrac{0.2\times (32)^2}{2\times 0.63}

P = 162.53 Watts

So, the power of the rattlesnake is 162.53 Watts. Hence, this is the required solution.

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The rate at which bus 1 is going is 55 mph

The rate at which bus 1 is going is 35 mph

Explanation:

As per the question:

Suppose, the distance traveled by Bus 1 be 'd' at the rate R after a time, t = 3h

Thus  

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d = Rt         (1)

Now, the total distance given is 270 miles:

d + d' = 270

Now, using eqn (1):

Rt + R't = 270

3(R + R - 20) = 270

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What is the frequency of an X-ray with wavelength 0.13 nm ? Assume that the wave travels in free space. Express your answer to t
dem82 [27]

Answer:

Frequency, f=2.30\times 10^{18}\ Hz

Explanation:

Given that,

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We need to find the frequency of an x-ray. All electromagnetic wave travel with a speed of light. It is given by the formula as :

c=f\lambda

f is the frequency

f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{0.13\times 10^{-9}}\\\\f=2.30\times 10^{18}\ Hz

So, the frequency of an x-ray is 2.30\times 10^{18}\ Hz. Hence, this is the required solution.

5 0
3 years ago
What is the gauge pressure in Pascals inside a honey droplet of a 0.1 cm diameter? Assume that air is surrounding this droplet a
Vikki [24]

Answer:

The gauge pressure in Pascals inside a honey droplet is 416 Pa

Explanation:

Given;

diameter of the honey droplet, D = 0.1 cm

radius of the honey droplet, R = 0.05 cm = 0.0005 m

surface tension of honey, γ = 0.052 N/m

Apply Laplace's law for a spherical membrane with two surfaces

Gauge pressure =  P₁ - P₀ = 2 (2γ / r)

Where;

P₀ is the atmospheric pressure

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Gauge pressure = 416 Pa

Therefore, the gauge pressure in Pascals inside a honey droplet is 416 Pa

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4 years ago
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