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Juliette [100K]
4 years ago
13

When a rattlesnake strikes, its head accelerates from rest to a speed of 32 m/s in 0.63 seconds. Assume for simplicity that the

only moving part of the snake is its head of mass 200 g. How much (average) power does the rattlesnake need to accelerate its head that fast?
Physics
1 answer:
irina [24]4 years ago
4 0

Answer:

Power, P = 162.53 Watts          

Explanation:

Given that,

Mass, m = 200 g = 0.2 kg

Initial speed of the snake, u = 0

Final speed of the snake, v = 32 m/s

Time, t = 0.63 s

Power of an object is given by :

P=\dfrac{W}{t}

P=\dfrac{\Delta K}{t}

P=\dfrac{mv^2}{2t}

P=\dfrac{0.2\times (32)^2}{2\times 0.63}

P = 162.53 Watts

So, the power of the rattlesnake is 162.53 Watts. Hence, this is the required solution.

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3 0
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if change in blood pressure between the brain and the feet is 1.88×10^4 pa .what will be the volume flow rate from head to feet
klio [65]

Answer: 3765.66 \frac{m^{3}}{s}

Explanation:

We can solve this problem using the <u>Poiseuille equation</u>:

Q=\frac{\pi r^{4}\Delta P}{8\eta L}

Where:

Q  is the Volume flow rate

r=23 cm \frac{1 m}{100 cm}=0.23 m  is the effective radius

L=6 ft \frac{0.3048 m}{1 ft}=1.8288 m  is the length

\Delta P=1.88(10)^{4} Pa  is the difference in pressure

\eta=3(10)^{-3} Pa.s is the viscosity of blood

Solving:

Q=\frac{\pi (0.23 m)^{4}(1.88(10)^{4} Pa)}{8(3(10)^{-3} Pa.s)(1.8288 m)}

Q=3765.66 \frac{m^{3}}{s}

4 0
4 years ago
A long wire is known to have a radius greater than 4.0 mm and to carry a current uniformly distributed over its cross section. i
ollegr [7]

Magnetic field outside it due to long wire is given by

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Now the ratio of two magnetic field is given by

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\frac{0.285}{0.200} = \frac{4*10}{R^2}

1.425 = \frac{40}{R^2}

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A piece of zinc was lying outside and had a temperature of 26 degrees C. Later that day the sun came out and the temperature inc
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Answer:

570 J

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