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aliya0001 [1]
3 years ago
14

You want to create 14.0 g of copper to meld into a piece of jewelry. You

Chemistry
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

3.4g of Al

Explanation:

you would need to start with 3.4 g of Al

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Giving brain thing
lana66690 [7]
I’m pretty sure the answer is C
5 0
3 years ago
Bugaboo can be oxidised to a carboxylic acid by heating with acidified potassium manganate (VII). Give the name and structural f
Novosadov [1.4K]

Answer:

See below.

Explanation:

CH3CH2CH2CH2OH is butanol.

The carboxylic acid formed , butyric acid has the formula:

CH3CH2CH2COOH.

Structural formula:

       H     H    H       O                  

        |       |      |        ||                      

H  -  C  -  C  -  C   -  C  -  OH

       |       |       |    

      H     H     H

8 0
3 years ago
The unsaturated hydrocarbon butadiene (C4H6) dimerizes to 4-vinylcyclohexene (C8H12). When data collected in studies of the kine
UkoKoshka [18]

Answer:

The dimerization of butadiene to 4-vinylcyclohexene folows second order kinetics and its rate law will be given by :

R=k[C_4H_6]^2

Explanation:

2C_4H_6\rightarrow C_8H_{12}

The rate of the reaction ;

R=k[C_4H_6]^x

As given in the question , that graph of time verses \frac{1}{[C_4H_6]} was linear but plots of [C_4H_6] or \ln[C_4H_6]  was curved.

Generally:

Graph of time verses [concentration] for zero order reaction is linear with negative slope.

Graph of time verses \ln [concentration] for secon order reaction is linear with negative slope.

Graph of time verses \frac{1}{[concentration]} for secon order reaction is linear with positive slope.

So, the dimerization of butadiene to 4-vinylcyclohexene folows second order kinetics and its rate law will be given by :

R=k[C_4H_6]^2

3 0
3 years ago
A super slow snail can travel 2.2cm in one minute. How far (in pm) can it travel in 24 hours? Please round to appropriate number
Cloud [144]

Answer : The distance covered by slow snail in 24 hours is 3.2\times 10^{13}pm

Explanation :

As we are given that the a slow snail can travel 2.2 cm in 1 minute. Now we have to calculate the distance covered by slow snail in 24 hours.

First we have to convert 24 hours in minutes.

Conversion used : (1 hour = 60 minutes)

As, 1 hour = 60 minutes

So, 24 hour = 24 × 60 minutes

                    = 1440 minutes

Now we have to calculate the distance covered by slow snail in 24 hours.

In 1 minute, the distance covered by slow snail = 2.2 cm

In 1440 minute, the distance covered by slow snail = 1440 × 2.2 cm

                                                                                     = 3168 cm

                                                                                     = 3.2\times 10^3cm

Now we have to convert 'cm' into 'pm'.

Conversion used : 1cm=10^{10}pm

As, 1cm=10^{10}pm

So,  3.2\times 10^3cm=\frac{3.2\times 10^3cm}{1cm}\times 10^{10}pm=3.2\times 10^{13}pm

Therefore, the distance covered by slow snail in 24 hours is 3.2\times 10^{13}pm

4 0
3 years ago
Calcium carbonate decomposes according to the following equation:
Bad White [126]

Answer:

CaCO3----------CaO+CO2

(40g+12g+16g×3) of CaCO3 produce (40g+16g) of CaO

100g of CaCO3 -----------------56g of CaO

20g of CaCO3-------------------x grams of CaO

x=(20g×56g)÷100g

x=1120gg÷100g

x=11.2g of CaO

Therefore, 11.2grams of CaO from 20grams of CaCO3

HOPE IT HELPED, PLEASE MARK BRAINLIEST

8 0
2 years ago
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