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2 years ago

You want to create 14.0 g of copper to meld into a piece of jewelry. You

Chemistry

1 answer:

Yuki888 [10]2 years ago

3 0

Answer:

3.4g of Al

Explanation:

you would need to start with 3.4 g of Al

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What is radium used for

Bas_tet [7]

Answer:

Radium is used to produce Radon

Explanation:

Radon is a gas used to treat cancer (certain types).

6 0

3 years ago

What volume of 1.60 M hydrochloric acid solution (HCI) is required to neutralize 48.0 mL of 0.200 M sodium

nexus9112 [7]

Answer:

Volume of HCl require = 6 mL

Explanation:

Given data:

Volume of HCl require = ?

Molarity of HCl solution = 1.60 M

Volume of NaOH = 48.0 mL

Molarity of NaOH = 0.200 M

Solution:

Formula:

M₁V₁ = M₂V₂

By putting values,

1.60 M×V₁ = 0.200 M×48.0 mL

V₁ = 0.200 M×48.0 mL/1.60 M

V₁ = 9.6 M .mL /1.60 M

V₁ = 6 mL

5 0

2 years ago

Many children are uncomfortable around white lab coats. Specifically explain why this occurs in what a doctor or dentist could d

zhannawk [14.2K]

Answer:

Sanitize

Explanation:

7 0

2 years ago

A thermometer having first-order dynamics with a time constant of 1 min is placed in a temperature bath at 100oF. After the ther

sveticcg [70]

Answer:

(a) See below

(b) 103.935 °F; 102.235 °F

Explanation:

The equation relating the temperature to time is

$T = T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )$

1. Calculate the thermometer readings after 0.5 min and 1 min

(a) After 0.5 min

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-0.5/1} \right )\\ & = & 100 + 10\left (1 - e^{-0.5} \right )\\ & = & 100 + 10 (1 - 0.6065)\\ & = & 100 + 10(0.3935)\\ & = & 100 + 3.935\\ & = & 103.935\,^{\circ}F\\\end{array}$

(b) After 1 min

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-1/1} \right )\\ & = & 100 + 10\left (1 - e^{-1} \right )\\ & = & 100 + 10 (1 - 0.3679)\\ & = & 100 + 10(0.6321)\\ & = & 100 + 6.321\\ & = & 106.321\,^{\circ}F\\\end{array}$

2. Calculate the thermometer reading after 2.0 min

T₀ =106.321 °F

ΔT = 100 - 106.321 °F = -6.321 °F

t = t - 1, because the cooling starts 1 min late

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-(t - 1)/\tau} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-(2 - 1)/1} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-1} \right )\\ & = & 106.321 - 6.321 (1 - 0.3679)\\ & = & 106.321 - 6.321 (0.6321)\\ & = & 106.321 - 3.996\\ & = & 102.325\,^{\circ}F\\\end{array}$

3. Plot the temperature readings as a function of time.

The graphs are shown below.

6 0

2 years ago

Minerals with the silicon-oxygen structure shown in Figure 2-1 are classified into what group?

egoroff_w [7]

B----------- oxide is the correct answer

6 0

2 years ago