What is the advantage of delivering electricity to homes through high voltage lines?

Chemistry

2 answers:

oksano4ka [1.4K]3 years ago

7 0

Delivering electricity to homes through high voltage lines, reduces the power loss that is caused by Joule's heating.

We know that:

P=VI

Where, P is power, V is the voltage and I is the current.

So if we keep P constant and make then voltage up, I must goes down.

According to Joule's first law : Power of heating generated by a conductor is directly proportional to the product of its resistance and the square of the current.

Now using the equation:

Q=I²Rt

Where Q is the heat generated, I is the current , R is the resistance and t is the time.

So by reduced I, heat loss will be reduced.

Leno4ka [110]3 years ago

7 0

The power loss due to Joule's heating is reduced in this case.

You might be interested in

Why do different isotopes of an element generally have the same physical and chemical properties?

tresset_1 [31]

Answer:

The correct answer is because they have same number of protons but different number of neutrons.

Explanation:

Isotopes are atoms of the same element but differ only in the number of neutrons in the nucleus, i.e. they have same atomic number but different mass number.

Mass number is affected as they have different number of neutrons, thus effecting their physical properties.

The number of electrons and protons are same, i.e. their atomic number is same and thus their chemical properties are same as chemical properties are determined by the atom’s electronic configuration and that relates to number of protons.

5 0

3 years ago

To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber

Alekssandra [29.7K]

Answer:

1.3 × 10³ cm³

Explanation:

The gas occupies a volume of V₁ = 310 cm³ under standard temperature and pressure (STP), that is, T₁ = 273.15 K and P₁ = 1.0 atm. In order to find the volume V₂ under different conditions we can use the combined gas law formula.

$\frac{P_{1}.V_{1}}{T_{1}} =\frac{P_{2}.V_{2}}{T_{2}} \\V_{2}=\frac{P_{1}.V_{1}.T_{2}}{T_{1}.P_{2}}=\frac{1.0atm\times 310cm^{3} \times 2473K }{273.15K \times 2.1atm} =1.3 \times 10^{3} cm^{3}$