Given:
m = 555 g, the mass of water in the calorimeter
ΔT = 39.5 - 20.5 = 19 °C, temperature change
c = 4.18 J/(°C-g), specific heat of water
Assume that all generated heat goes into heating the water.
Then the energy released is
Q = mcΔT
= (555 g)*(4.18 J/(°C-g)*(19 °C)
= 44,078.1 J
= 44,100 J (approximately)
Answer: 44,100 J
12 ounce hard seltzer and 1.5 ounces of liquor are standard drinks because they contain the <u>same amount</u><u> </u><u>of </u><u>pure alcohol</u>
<h3>What is standard drink?</h3>
This is a term used to refer to the measure of alcoholic content of drinks such that the drink should have 14 grams of pure alcohol or 0.6 fluid ounces of pure alcohol. This concept of standard drink is applicable in the United States of America.
The equivalence of a standard drink is 5 percent alcohol as seen in regular beer, 12 percent as seen in wines, and 40 percent as seen in distilled spirits. This measurement in taken by the percentage of the total volume of the beverage. hence the quantity of the drink or beverage may be different as the percentage is what determines the amount of alcohol present
From standard drink chart both drinks has same amount of pure alcohol so they are said to be standard drinks
Read more on standard drinks here: brainly.com/question/17645986
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Answer:
The bus
Explanation:
a = (v-u)/t
Where
a = acceleration
v = final velocity
u = initial velocity
t = time taken
For truck to get its acceleration,
a = (18-0)/5.5 = 3.27 ms⁻²
For bus to get its acceleration,
a = (24-0)/6 = 4 ms⁻²
As 4 > 3.27 bus has a greater acceleration.
I think the answer is c) 1
Hope it helps and have a good day
