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nikdorinn [45]
3 years ago
6

A resistor R1 is wired to a battery, then resistor R2 is added in series. Are (a) the potential difference across R1 and (b) the

current i1 through R1 now more than, less than, or the same as previously? (c) Is the equivalent resistance R12 of R1 and R2 more than, less than, or equal to R1?
Physics
1 answer:
tia_tia [17]3 years ago
6 0

Answer:

Explanation:

a ) Earlier emf of cell applied on R₁ but now emf will be distributed among R₁ and R₂

Potential difference on R₁ will become less .

b ) Current is inversely proportional to resistance of the circuit. As resistance increases , current will be less . So current through R₁ will become less.

c )

When resistance is added in series , they are added up to obtain equivalent resistance . So equivalent resistance R₁₂ will be more than R₁ OR R₂.

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The GPE of a 70kg person standing on a chair 1m off the ground is how many joules?
Artemon [7]
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3 years ago
An ice skater starts with a velocity of 2.25 m/s in a 50.0 direction. after 8.33 m/s in a 120 direction. what is the y-component
Bond [772]

The y-component of the acceleration is 0.33 m/s^2

Explanation:

The y-component of the acceleration is given by:

a_y = \frac{v_y-u_y}{t}

where

v_y is the y-component of the  final velocity

u_y is the y-component of the initial velocity

t is the time elapsed

For the ice skater in this problem, we have:

u_y = u sin \theta_1 = (2.25 m/s)(sin 50.0^{\circ})=1.72 m/s

where

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v_y = v sin \theta_2 = (4.65)(sin 120^{\circ})=4.03 m/s, where

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a_y=\frac{4.03-1.72}{8.33}=0.33 m/s^2

Learn more about acceleration:

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brainly.com/question/2562700

#LearnwithBrainly

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