The metal = Platinum(Pt)
<h3>Further explanation</h3>
FCC : Face centered cubic : the unit structures of the unit cell((other than BCC, HCP)
In FCC ⇒ atoms on every corner and side (total 4 atoms)
The length of the face diagonal (b) = 4 times the atomic radius (r)
Formula :
![\tt b=4r](https://tex.z-dn.net/?f=%5Ctt%20b%3D4r)
![\tt a=r\sqrt{8}](https://tex.z-dn.net/?f=%5Ctt%20a%3Dr%5Csqrt%7B8%7D)
![\tt V=16r\sqrt{2}=a^3](https://tex.z-dn.net/?f=%5Ctt%20V%3D16r%5Csqrt%7B2%7D%3Da%5E3)
![\tt \rho=\dfrac{n.Ar}{V.No}](https://tex.z-dn.net/?f=%5Ctt%20%5Crho%3D%5Cdfrac%7Bn.Ar%7D%7BV.No%7D)
Ar = atomic mass, g/mol
No = Avogadro number = 6.02.10²³
n = number of atoms
V = volume (cm³)
a = side length
b = diagonal of the side surface
r = atomic radius
a= 392 pm=3.92 x 10⁻⁸ cm
ρ = 21.45 g/cm³
![\tt V=a^3\\\\V=(3.92\times 10^{-8})^3\\\\V=6.024\times 10^{-23}~cm^3](https://tex.z-dn.net/?f=%5Ctt%20V%3Da%5E3%5C%5C%5C%5CV%3D%283.92%5Ctimes%2010%5E%7B-8%7D%29%5E3%5C%5C%5C%5CV%3D6.024%5Ctimes%2010%5E%7B-23%7D~cm%5E3)
The atomic mass :
![\tt 21.45~g/cm^3=\dfrac{4\times Ar}{6.024\times 10^{-23}\times 6.02\times 10^{23}}\\\\Ar=194.47\approx 195~g/mol](https://tex.z-dn.net/?f=%5Ctt%2021.45~g%2Fcm%5E3%3D%5Cdfrac%7B4%5Ctimes%20Ar%7D%7B6.024%5Ctimes%2010%5E%7B-23%7D%5Ctimes%206.02%5Ctimes%2010%5E%7B23%7D%7D%5C%5C%5C%5CAr%3D194.47%5Capprox%20195~g%2Fmol)
radius :
![\tt a=r\sqrt{8}\\\\3.92\times 10^{-8}=r\sqrt{8}\\\\r=1.386\times 10^{-8}~cm](https://tex.z-dn.net/?f=%5Ctt%20a%3Dr%5Csqrt%7B8%7D%5C%5C%5C%5C3.92%5Ctimes%2010%5E%7B-8%7D%3Dr%5Csqrt%7B8%7D%5C%5C%5C%5Cr%3D1.386%5Ctimes%2010%5E%7B-8%7D~cm)
Element with atomic mass 195 g/mol and radius = 139 pm (1.386x10⁻⁸cm) = Platinum(Pt)
Answer:
the structure of an atom, theoretically consisting of a positively charged nucleus surrounded and neutralized by negatively charged electrons revolving in orbits at varying distances from the nucleus, the constitution of the nucleus and the arrangement of the electrons differing with various chemical elements.
Explanation:
Answer is: boiling point will be changed by 4°C.
Chemical dissociation of aluminium nitrate in water: Al(NO₃)₃ → Al³⁺(aq) + 3NO⁻(aq).
Change in boiling point: ΔT =i · Kb · b.
Kb - molal boiling point elevation constant of water is 0.512°C/m, this the same for both solution.
b - molality, moles of solute per kilogram of solvent., this is also same for both solution, because ther is same amount of substance.
i - Van't Hoff factor.
Van't Hoff factor for sugar solution is 1, because sugar do not dissociate on ions.
Van't Hoff factor for aluminium nitrate solution is approximately 4, because it dissociates on four ions (one aluminium cation and three nitrate anions). So ΔT is four times bigger.
Number 2 is the correct answer
Answer:
The scientific method is a system of reasoning. You can make reasonable explanations for something that you are observing in the world.
Explanation: