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fomenos
3 years ago
15

What effect does gravity have on a slinky​

Chemistry
1 answer:
True [87]3 years ago
8 0

If you consider the motion of the slinky as just one object, you can look at it's center of mass. From the whole slinky point of view, there is only one force on the slinky - the gravitational force. This means that it falls and accelerates downward with an acceleration of -9.8 m/s2 just like all free-falling objects. Plze mark brainiest

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A(n) ________ acid is an acid that can leave solution and enter the atmosphere. a(n) ________ acid is an acid that can leave sol
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A volatile acid is an acid that can leave solution and enter the atmosphere.


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3 years ago
What is another name for a beta minus (B-) particle?
pentagon [3]
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Suppose that the physical properties of two stars are identical in every way --- for example, same distance, same mass, same tem
larisa [96]

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By measuring it's Radical velocity using Doppler Phenomenon...

Explanation:

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Laurie is moving a dresser with a mass of 250kg. She does 126 J of work with a force of 14 N. How far does she move the dresser?
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7 0
3 years ago
A gas within a piston–cylinder assembly undergoes an isothermal process at 400 K during which the change in entropy is −0.3 kJ/K
Karolina [17]

Answer:

W = -120 KJ

Explanation:

Since the piston–cylinder assembly undergoes an isothermal process, then the temperature is constant.

Thus; T1 = T2 = 400K

change in entropy; ΔS = −0.3 kJ/K

Formula for change in entropy is written as;

ΔS = Q/T

Where Q is amount of heat transferred.

Thus;

Q = ΔS × T

Q = -0.3 × 400

Q = -120 KJ

From the first law of thermodynamics, we can find the workdone from;

Q = ΔU + W

Where;

ΔU is Change in the internal energy

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Now, since it's an ideal gas model, the change in internal energy is expressed as;

ΔU = m•C_v•ΔT

Where;

m is mass

C_v is heat capacity at constant volume

ΔT is change in temperature

Now, since it's an isothermal process where temperature is constant, then;

ΔT = T2 - T1 = 0

Thus;

ΔU = m•C_v•ΔT = 0

ΔU = 0

From earlier;

Q = ΔU + W

Thus;

-120 = 0+ W

W = -120 KJ

8 0
3 years ago
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