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weqwewe [10]
4 years ago
11

Consider the following setup with three identical springs, a ruler for length measurements and three known masses and three unkn

own masses. You previously explored the force applied by the spring on a mass by hanging each of the known masses on a separate identical spring to determine the spring constant kk. Here we want to determine the mass of some unknowns. You hang each of the unknown colored masses on the same springs you characterized previously. From the displacement of the springs from the original equilibrium position, what is the mass of the green mass
Physics
1 answer:
svetlana [45]4 years ago
4 0

Answer:

To find the value of the unknown weight, we previously placed the 3 known weights and made a graph of the force against displacement

When hanging the weight is known, we measure the displacement and from the graph we can find the value of the hanging masses

We can also use the equation and multiply the constant K by the displacement and this is the applied weight.

Explanation:

For this problem we will use the translational equilibrium relation

        F –W = 0

        F = W

        W = mg

The spring elastic force is

        F = - k x

We substitute

        k x = m g

Where we see that the force of the spring is equal to the weight of the body.

To find the value of the unknown weight, we previously placed the 3 known weights and made a graph of the force against displacement

When hanging the weight is known, we measure the displacement and from the graph we can find the value of the hanging masses

We can also use the equation and multiply the constant K by the displacement and this is the applied weight.

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Two balls have masses 18 kg and 47 kg. The 18 kg ball has an initial velocity of 76 m/s (to the right) along a line joining the
BigorU [14]

Answer:

The final velocity of 18 kg ball is V_{2} = 42.09 \frac{m}{sec}

Explanation:

Mass of first ball m_{1} = 18 kg

Mass of second ball m_{2} = 47 kg

Initial velocity of 18 kg ball V_{1} = 76 \frac{m}{sec}

Initial velocity of 47 kg ball = 0

Final velocity of 18 kg ball V_{2} = ??

Final velocity of 18 kg ball  is given by the formula

V_{2} = \frac{2 m_{1} V_{1} }{m_{1} + m_{2}  }

Put all the values in above formula we get

V_{2} = 2 × 18 × \frac{76}{65}

V_{2} = 42.09 \frac{m}{sec}

Thus, the final velocity of 18 kg ball is V_{2} = 42.09 \frac{m}{sec}

3 0
3 years ago
Electrons (mass m, charge –e) are accelerated from rest through a potential difference V and are then deflected by a magnetic fi
adell [148]

Answer:

r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}

Explanation:

Let m and e are the mass and charge of an electron. It is accelerated from rest through a potential difference V and are then deflected by a magnetic field that is perpendicular to their velocity. Let v is the velocity of the electron. It can be calculated as :

\dfrac{1}{2}mv^2=eV

v=\sqrt{\dfrac{2eV}{m}}

When the electron enters the magnetic field, the centripetal force is balanced by the magnetic force as :

\dfrac{mv^2}{r}=evB

r=\dfrac{mv}{eB}

or

r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}

So, the radius of the resulting electron trajectory is \dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}. Hence, this is the required solution.

8 0
3 years ago
An object is thrown horizontally off a cliff with an initial velocity of 5.0 meters per second. the object strikes the ground 3
shutvik [7]
Speed is not a vector so horizontal speed does not sighify anything. If u meant velocity it vill be same as the initial velocity in horizontal direction
7 0
4 years ago
Read 2 more answers
The figure above shows the net force exerted on an object as a function of the position of the object. The object starts from re
weqwewe [10]

Answer:

0.06 Kg

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 3.0 m/s

Distance (s) = 0.09 m

Net Force (F) = 3 N

Mass (m) =?

Next, we shall determine the acceleration of the object. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 3.0 m/s

Distance (s) = 0.09 m

Acceleration (a) =?

v² = u² + 2as

3² = 0² + (2 × a × 0.09)

9 = 0 + 0.18a

9 = 0.18a

Divide both side by 0.18

a = 9 / 0.18

a = 50 m/s²

Finally, we shall determine the mass of the object. This can be obtained as follow:

Net Force (F) = 3 N

Acceleration (a) = 50 N

Mass (m) =?

F = ma

3 = m × 50

Divide both side by 50

m = 3 / 50

m = 0.06 Kg

Therefore, the mass of the object is 0.06 Kg

5 0
3 years ago
3. A 142 g baseball is thrown at a speed of 42.9 m/s. What is the kinetic energy of the baseball at this moment?
krok68 [10]
Kinetic energy=1/2mv^2
=1/2(142*10^-3)(42.9)^2=130.6=131J
8 0
3 years ago
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