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weqwewe [10]
4 years ago
11

Consider the following setup with three identical springs, a ruler for length measurements and three known masses and three unkn

own masses. You previously explored the force applied by the spring on a mass by hanging each of the known masses on a separate identical spring to determine the spring constant kk. Here we want to determine the mass of some unknowns. You hang each of the unknown colored masses on the same springs you characterized previously. From the displacement of the springs from the original equilibrium position, what is the mass of the green mass
Physics
1 answer:
svetlana [45]4 years ago
4 0

Answer:

To find the value of the unknown weight, we previously placed the 3 known weights and made a graph of the force against displacement

When hanging the weight is known, we measure the displacement and from the graph we can find the value of the hanging masses

We can also use the equation and multiply the constant K by the displacement and this is the applied weight.

Explanation:

For this problem we will use the translational equilibrium relation

        F –W = 0

        F = W

        W = mg

The spring elastic force is

        F = - k x

We substitute

        k x = m g

Where we see that the force of the spring is equal to the weight of the body.

To find the value of the unknown weight, we previously placed the 3 known weights and made a graph of the force against displacement

When hanging the weight is known, we measure the displacement and from the graph we can find the value of the hanging masses

We can also use the equation and multiply the constant K by the displacement and this is the applied weight.

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What force will counterbalance two forces 4.0 N and 5.0 N acting perpendicular to each other?​
beks73 [17]

The force that will counterbalance two forces 4.0 N and 5.0 N acting perpendicular to each other is a force of 6.4 N acting in an opposite direction to the resultant of the two forces.

<h3>Equilibrant of forces</h3>
  • The equilibrant of two or more forces is that single force which will have the same effect as the resultant of two or more forces but which is acting in a direction opposite to that of the resultant force.

The Resultant of the two forces 4.0 N and %.0 N acting perpendicular to each other is calculated using the formula:

R² = A² + B²

where A and B are the two forces acting perpendicular to each other.

R² = 4² + 5²

R² = 41

R = 6.4 N

Therefore, the force that will counterbalance two forces 4.0 N and 5.0 N acting perpendicular to each other is a force of 6.4 N acting in an opposite direction to the resultant of the two forces.

Learn more about resultant and equilibrant forces at: brainly.com/question/8045102

3 0
3 years ago
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Which of the following is an accurate statement?
cestrela7 [59]
A OR D ARE THE TWO ANSWERS I THINK
4 0
3 years ago
1. A 3.0 kg mass is tied to a rope and swung in a horizontal circle. If the velocity of the mass is 4.0 ms and
saul85 [17]

10.67m/s²

32N

Explanation:

Given parameters:

Mass of the body = 3kg

velocity of the mass = 4m/s

radius of circle = 0.75m

Unknown:

centripetal acceleration = ?

centripetal force = ?

Solution:

The centripetal force is the force that keeps a radial body in its circular motion. It is directed inward:

   Centripetal acceleration  = \frac{v^{2} }{r}

   v is the velocity of the body

    r is the radius of the circle

  putting in the parameters:

   Centripetal acceleration = \frac{4^{2} }{0.75}

    Centripetal acceleration = 10.67m/s²

Centripetal force = m  \frac{v^{2} }{r}

          m is the mass

 Centripetal force = mass x centripetal acceleration

                              = 3 x 10.67

                              = 32N

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

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3 years ago
Consider a car parked on a hill and pick the axis of rotation (i.e., the pivot point) to pass through the points where the front
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Answer:d

Explanation:

Torque of Frictional force will be zero

\tau _{f_1}=zero

\tau_{f_2}=zero

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The other force which will create torque about Pivot point is Normal Force on second tire

Torque due to Normal Reaction \tau _N=N_2\times y

Thus Normal Force on back tires of car will create torque about this same axis.        

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An alarm clock draws 0.5 A of current when connected to a 120 volt circuit. Calculate its resistance.
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