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3 years ago

You are stirring a pot with a metal spoon. The spoon becomes hot in your hand. what type of heat transfer is this

Chemistry

1 answer:

Alexxandr [17]3 years ago

4 0

Conduction

Explanation:

Stirring a pot with a metal spoon thereby making the spoon hot in the hand is a mode of heat transfer called conduction.

Heat is form of energy that causes differences in temperature between two bodies.

There are three modes of heat transfer which are conduction, convection and radiation.
Radiation is a form of heat transfer that does not involve a material medium.
Convection is heat transfer in fluids that involves movement of the materials of the medium.
Conduction is a mode of heat transfer in solids that involves movement of the materials of the medium.

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Heat transfer from sun brainly.com/question/1140127

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The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C

Kipish [7]

Answer: 72 grams of $O_2(g)$ are needed to completely burn 19.7 g $C_3H_8(g)$

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Putting in the values we get:

$\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles$

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$

According to stoichiometry:

1 mole of $C_3H_8$ requires 5 moles of oxygen

0.45 moles of $C_3H_8$ require= $\frac{5}{1}\times 0.45=2.25$ moles of oxygen

Mass of $O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g$

72 grams of $O_2(g)$ are needed to completely burn 19.7 g $C_3H_8(g)$

7 0

3 years ago

I need help fast plzzzzzzzzz

sineoko [7]

What’s the question?

6 0

2 years ago

A 10-liter [l] flask contains 1.4 moles [mol] of an ideal gas at a temperature of 20 degrees celsius [degreesc]. What is th

Lynna [10]

The pressure in the flask is 3.4 atm.

pV = nRT

T = (20 + 273.15) K = 293.15 K

p = (nRT)/V = (1.4 mol × 0.082 06 L·atm·K⁻¹mol⁻¹ × 293.15 K)/10 L = 3.4 atm

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2 years ago

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One gram of alum, KAl(SO4)2.12H2O, contains 1.3 × 1021 Al atoms. How many oxygen atoms are contained in 1.0 g alum?

Roman55 [17]

From the chemical formula, 1 formula unit of KAl (SO4)2.12H2O encompasses 1 atom of Al = 4 * 2 atoms of O in KAl (SO4)2 + 12 atoms of O in 12H2O which is equal to 20 atoms of O.

So, if you have 1.3 × 10^21 Al atoms, you have 20 * 1.3 × 10^21 O atoms will now be equal to 2.6 * 10^22 atoms of O.

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3 years ago

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Consider a balloon of nitrogen gas and a crystal of sugar sitting on a table at room conditions. Select the appropriate statemen

yKpoI14uk [10]

Answer:

about the same

Explanation:

Thermal energy is constant at a certain temperature in general. The energy is denoted by $K_BT$

Where,

$K_B$ is the Boltzmann constant

T is the absolute temperature

Given that the balloon filled with nitrogen gas and the crystal of sugar are at room conditions means that they have same conditions and thus they will possess same energy irrespective of the states of the matter.

Thus,

The thermal energy of the sugar molecules is about the same as that of nitrogen molecules.

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3 years ago