The molarity of KOH is 0.1055 M
<u><em> calculation</em></u>
Step 1: write the equation for reaction between H₂C₂O₄.2H₂O and KOH
H₂C₂O₄.2H₂O + 2 KOH → K₂C₂O₄ +4 H₂O
step 2: find the moles of H₂C₂O₄.2H₂O
moles = mass÷ molar mass
from periodic table the molar mass H₂C₂O₄.2H₂O= (1 x2) +(12 x2) +(16 x4) + 2(18)=126 g/mol
= 0.2000 g ÷ 126 g/mol =0.00159 moles
step 3: use the mole ratio to calculate the moles of KOH
H₂C₂O₄.2H₂O : KOH is 1:2
therefore the moles of KOH =0.00159 x 2 = 0.00318 moles
step 4: find molarity of KOH
molarity = moles/volume in liters
volume in liters = 30.12/1000=0.03012 L
molarity is therefore = 0.00318/0.03012 =0.1055 M
A physical property is a property that does not change the original substance, meaning that it does not break any bonds, nor for any new ones. Though, a physical property can be changing the substances state of matter.
When you are boiling water, you are changing its state to go from a liquid to a gas. The temperature is not a characteristic physical property because it doesn't help us know a lot about that substance, in other words, it isn't significant to the substance. Same goes for volume.
The SI unit for volume is cubic meters of M^3
Answer is: nucleus of Cd is 1.26 times greater.
The Nuclear radius formula or radius of nucleus formula: R = R₀ · ∛A.
R is nuclear radius.
R₀ is empirical constant, R₀ = 1.2 10⁻¹⁵ m.
A is number of nucleon.
R(Fe) = 1.2·10⁻¹⁵ m · ∛56.
R(Fe) = 4.59·10⁻¹⁵ m.
R(Cd) = 1.2·10⁻¹⁵ m · ∛112.
R(Cd) = 5.78·10⁻¹⁵ m.
R(Cd) / R(Fe) = 5.78·10⁻¹⁵ m / 4.59·10⁻¹⁵ m.
R(Cd) / R(Fe) = 1.26.
Answer:
1,42M
Explanation:
Molar concentration is given in moles of solute per liter o solution. Assuming you have 100g of solution:
10g KCl × (1mol / 74,55g) = <em>0,134 moles of KCl</em>
As you have 100g of solution:
100g × (1mL / 1,06g) × (1L / 1000mL) = <em>0,0943L</em>
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That means molar concentration is:
0,134 moles of KCl / 0,0943L = <em>1,42M</em>
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I hope it helps!
