Answer:
Concentration of the resulting solution = 2.04 M
Explanation:
<u>Data:</u>
M1 = 5.10 M
V1 = 200.0 mL
V2 = 500.0 mL
M2 = ?
By modifying the volume of solution, keeping the amount of solute constant, the concentration changes. To perform the calculations, the equation will be:
Where M1 is the initial concentration of the solution, M2 the final concentration and V is the value of the volumes of the initial and final solution.
Clearing the value of M2 from the equation and replacing the values we have:
Answer:
7.00
Explanation:
When the solutions are mixed, the HCl dissociates to form the ions H+ and Cl-. The ion H+ will react with the NH3 to form NH4+. The stoichiometry for this is 1 mol of HCl to 1 mol of H+ to 1 mol of Cl-, and 1 mol of H+ to 1 mol of NH3 to 1 mol of NH4+.
First, let's find the number of moles of each one of them, multiplying the concentration by the volume:
nH+ = 0.15 M * 25 mL = 3.75 mmol
nNH3 = 0.52 M * 25 mL = 13 mmol
So, all the H+ is consumed, and the neutralization is completed, thus pH will be the pH of the solvent (water), pH = 7.00.
A) The alkali metal atoms forms a +1 ion, while the alkaline eaeth metal atom forms a +2 ion.
It will lose them and become stable
Answer:
10 core 2 valence
Explanation:
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