Given that force is applied at an angle of 30 degree below the horizontal
So let say force applied if F
now its two components are given as


Now the normal force on the block is given as



now the friction force on the cart is given as



now if cart moves with constant speed then net force on cart must be zero
so now we have




so the force must be 199.2 N
In practice, something that follows a very predictable pattern can be used as a time standard. This include things like radioactive decay, planetary orbit, and the speed of light, among others.
We know, F = m * a
F = 10 * 5
F = 50 N
In short, Your Answer would be 50 Newtons
Hope this helps!
Answer:
Explanation:
Given
Horizontal bar rises with 300 mm/s
Let us take the horizontal component of P be


where
is angle made by horizontal bar with x axis
Velocity at y=150 mm

thus 
position of


Velocity at this instant


<u><em>Kinetic Energy Pulls Any object to the ground.This Energy is a part of Gravity.</em></u>
<u><em>Wish you happy timez!</em></u>