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dezoksy [38]
4 years ago
14

A cube measures 1.0 cm on each side. What is the volume of the cube? If this cube is dropped into 28.0 ML of water, what will be

the new volume reading on the graduated cylinder?
Physics
1 answer:
Sonja [21]4 years ago
7 0
Volume of cube = Length x width x height
                          = 1 x 1 x 1
                          = 1 cm cubed.
If this cube is dropped into 28.0 ML of water the new volume reading onthe graduated cylinder = 1 + 28 
                                     = 29 mL
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On a highway, a car is driven 80. kilometers
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The average speed of the car for the entire trip can be calculate by using:

v=\frac{S}{t}

where S is the total distance covered by the car, and t is the total time taken.


The total distance travelled by the car is:

S=80 km+50 km+40 km=170 km

while the total time taken is:

t=1.00 h+0.50 h+0.50 h=2.00 h


so, the average speed of the car is:

v=\frac{S}{t}=\frac{170 km}{2.00 h}=85 km/h


so, the correct answer is (3) 85 km/h.

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Answer:

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What happens to ocean water as it moves from Antarctica to the equator?
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It becomes less dense and rises to the surface

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At the instant the traffic light turns green, an automobile that has been waiting at an intersection starts ahead with a constan
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Answer:

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(B) Final speed of the automobile is 29.6 m/s.

Explanation:

According to the problem, the automobile is at rest, so its initial speed is zero and the automobile is moving with constant acceleration.

The general equation of motion is:

d = ut + 0.5at²      .....(1)

Here d is distance, a is acceleration, t is time and u is initial speed.

The distance (d₁) travel by the automobile after green light in time t is given by the relation :

d₁ = u₁t + 0.5at²

We know that its initial velocity is zero i.e. u = 0 m/s.

d₁ = 0.5at²      ......(2)

The truck is moving with constant speed, so its acceleration is zero. Therefore, the distance covered by the truck using equation (1) is;

d₂ = u₂t         .......(3)

Since, the distance travelled by automobile and truck are same. Hence,

d₁ = d₂

0.5at² = u₂t

t = 2u₂/a

Substitute 14.8 m/s for u₂ and 2.50 m/s² for a in the above equation.

t = \frac{2\times14.8}{2.50}

t = 11.84 s

(A) Distance travelled by automobile, d = u₂t =14.8 x 11.84 = 175.23 m

(B) Final speed of the automobile is given by the relation:

v = u + at

v = 0 + 2.50 x 11.84

v = 29.6 m/s

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hope it helps

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