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3 years ago

In Motion studies, the position in space and time at which motion began is selected as the ______.

Physics

2 answers:

Sonbull [250]3 years ago

6 0

I am pretty sure that the answer is B.

nydimaria [60]3 years ago

4 0

Answer:

b) origin

Explanation:

Motion is when a body changes position in space with respect to time. There are four types of motion namely

1. circular motion: this is the motion of an object along a circular path eg. the motion of a car tyre.

2. random motion: it is the motion of a body in zigzag manner e.g the motion of smoke from the exhaust pipe of a vehicle as it rises into the atmosphere

3. oscillatory : also known as the to and fro movement of a body e.g a pendulum swing

4. Linear motion: The motion of a body on a straight line. also known as translational motion e.g the motion of a car

Parameters/ terminologies used in motion are

velocity

displacement

distance

acceleration,

time,

speed

Motion in space and time starts from a point known as Origin

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umka2103 [35]

Answer:

$x=2.4365\ m$

and

$x=-1.4365\ m$

Explanation:

Given:

first charge, $q_1=5\times 10^{-3}\ C$

second charge, $q_2=3\times 10^{-3}\ C$

position of first charge, $x_1=-2\ m$

position of second charge, $x_2=-1\ m$

Now since there are only 2 charges and of the same sign so they repel each other. This repulsion will be zero at some point on the line joining the charges.

<u>Now, according to the condition, electric field will be zero where the effects of field due to both the charges is equal.</u>

$E_1=E_2$

since first charge is greater than the second charge so we may get a point to the right of the second charge and the distance between the two charges is 1 meter.

$\frac{1}{4\pi.\epsilon_0} \frac{q_1}{(r+1)^2} =\frac{1}{4\pi.\epsilon_0} \frac{q_2}{(r)^2}$

$\frac{5\times 10^{-3}}{(r+1)^2} = \frac{3\times 10^{-3}}{(r)^2}$

$3(r^2+1+2r)=5r^2$

$2r^2-6r-3=0$

$r=3.4365 \&\ r=-0.4365$

Since we have assumed that the we may get a point to the right of second charge so we calculate with respect to the origin.

$x=-1+3.4365=2.4365\ m$

and

$x=-1-0.4365=-1.4365\ m$

6 0

2 years ago

What help in reversing direction of current of current

Novay_Z [31]

Answer:

<em>To reverse the direction of an electric current, we simply reverse the voltage either automatically with the help of some switching circuitry or manually by changing the voltage source terminals connection. </em>

Explanation:

For electric current to flow, there must be a potential difference, usually referred to as the voltage. The electric current flow is analogous to the flow of water under the action of a pump, through a series of pipe connections. The voltage is similar to the driving action of the pump, and current flows the same way water flows. The resistance due to drag on the pipe wall is equivalent to electric resistance. For current to flow in the reverse direction, the voltage or rather, the potential difference is changed, causing the current to flow in the opposite direction. This can be done by switching the terminals of the voltage source, or by automatic means. The automatic switching can be done with a transistor based circuitry.

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3 years ago

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alexdok [17]

Answer:

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Explanation:

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2 years ago

What renewable source of energy would be suited to chicago IL?

Kay [80]

Answer:

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Explanation:

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When Mendeleev organized elements in his periodic table in order of increasing mass, similar elements with similar properties we

Temka [501]

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