1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bezimeni [28]
3 years ago
9

Yo-Yo man releases a yo-yo from rest and allows it to drop, as he keeps the top end of the string stationary. The mass of the yo

-yo is 0.056 kg, its moment of inertia is 2.9×10−5kg⋅m2 and the radius, r, of the axle the string wraps around is 0.0064 m.
Through what height must the yo-yo fall for its linear speed to be 0.75 m/s ?
Physics
1 answer:
patriot [66]3 years ago
6 0

To solve this problem it is necessary to use the conservation equations of both kinetic, rotational and potential energy.

By definition we know that

KE + KR = PE

Where,

KE =Kinetic Energy

KR = Rotational Kinetic Energy

PE = Potential Energy

In this way

\frac{1}{2} mv^2 +\frac{1}{2} I\omega^2 = mgh

Where,

m = mass

v= Velocity

I = Moment of Inertia

\omega = Angular velocity

g = Gravity

h = Height

We know as well that \omega = v/r for velocity (v) and Radius (r)

Therefore replacing we have

\frac{1}{2} mv^2 +\frac{1}{2} I\omega^2 = mgh

[tex]h= \frac{1}{2} \frac{v^2}{g} +\frac{1}{2} \frac{I}{mg}(\frac{v}{r})^2[/tex]

h= \frac{1}{2}v^2 ( \frac{1}{g} +\frac{I}{mg}\frac{1}{r^2} )

h= \frac{1}{2}0.75^2 ( \frac{1}{9.8} +\frac{2.9*10^{-5}}{(0.056)(9.8)}\frac{1}{(0.0064)^2} )

h = 0.3915m

Therefore the height must be 0.3915 for the yo-yo fall has a linear speed of 0.75m/s

You might be interested in
In the year 1178. five monks at Canterbury Cathedral in England observed what appeared to be an asteroid colliding with the moon
Lubov Fominskaja [6]

Answer: 1.28 sec

Explanation:

Assuming that the glow following the collision was produced instantaneously, as the light propagates in a straight line from Moon to the Earth at a constant speed, we can get the time traveled by the light applying velocity definition as follows:

V = ∆x / ∆t

Solving for ∆t, we have:

∆t = ∆x/v = ∆x/c = 3.84 108 m / 3.8 108 m/s = 1.28 sec

8 0
3 years ago
What is the current hypothesis on how the earths moon formed
Gwar [14]
The earth and moon were created By a collision between two planetary objects Each five time the size of mars. Is the newest hypothesis. 
4 0
3 years ago
Read 2 more answers
A uniformly charged, straight filament 7.00m in length has a total positive charge of 2.00μC. An uncharged card-board cylinder 2
TEA [102]

The electric field at the surface of the cylinder is 51428V/m

Given data:

• The length of the charge is l=  7m.

• The charge is q = 2μC..

• The radius the cylinder is r = 10 cm

Since the filament length is so large as compared to the cylinder length that the infinite line of charge can be assumed.

The expression to calculate the electric field is given as,

E=2kλ/r

Here, λ is the linear charge density.

Substitute the values in the above equation,

E = (2×9×109N⋅m^2/C^2×2×10^−6C)/0.1m×7m

E = 51428N/C×(V/m)/(N/C)

=51428V/m

An electric charge is the property of matter where it has more or fewer electrons than protons in its atoms. Electrons carry a negative charge and protons carry a positive charge. Matter is positively charged if it contains more protons than electrons, and negatively charged if it contains more electrons than protons.

Learn more about charge here:

brainly.com/question/19886264

#SPJ4

4 0
1 year ago
Please help on this one?
Schach [20]

Chemical energy. Elimination is useful to answer this question.

6 0
3 years ago
A cart's initial velocity is +3.0 meters per second. What is its final velocity after accelerating at a rate of 1.5 m/s2 for 8.0
Katarina [22]

Answer:

V = 15m/s

Explanation:

Given the following data;

Initial velocity = 3m/s

Time = 8secs

Acceleration = 1.5m/s²

To find the final velocity, we would use the first equation of motion;

V = U + at

Substituting into the equation, we have

V = 3 + 1.5*8

V = 3 + 12

V = 15m/s

6 0
2 years ago
Other questions:
  • For the airfoil and conditions in Problem 2.2, calculate the lift-to-drag ratio. Comment on its magnitude.
    12·1 answer
  • Calculate the magnitude of the normal force on a 25.2 kg block in the following circumstances. (Enter your answers in N.) HINT (
    11·1 answer
  • True or False:
    6·1 answer
  • An ion of an element has 30 protons 32 neutrons and 29 electrons what is that charge and how did you make that determination
    13·2 answers
  • Magnetic attraction is one of the chemical properties of matter *<br><br> True<br> False
    10·1 answer
  • Which object has the least amount of Kinect energy
    11·1 answer
  • A team of eight dogs pulls a sled with waxed wood runners on wet snow (mush!). The dogs have average masses of 19.0 kg, and the
    5·1 answer
  • A person desires to reach a point that is 2.17 km from her present location and in a direction that is 29.6° north of east. Howe
    15·1 answer
  • What part of the Milky Way allows for determination of its rotational direction? A. Celestial body B. Galactic body C. Galactic
    13·2 answers
  • How many components can be realized of a vector?​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!