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mr Goodwill [35]
3 years ago
13

What occurs when a 35-gram aluminum cube at 100.°C is placed in 90. grams of water at 25°C in an insulated cup?

Chemistry
1 answer:
posledela3 years ago
8 0
Heat always flows from hot to cold. The aluminum is hotter than the water in the cup so the answer is 2: The heat is transferred from the aluminum to the water, and the temperature of the water increases.
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What gas is used in freezers and fridges? ​
natta225 [31]

Answer:

Chloro-Flouro-Carbon

Explanation:

Chloro-Flouro-Carbon (CFC Gas) is used as a refrigerant in fridges and freezers.

7 0
2 years ago
A sample of a uranium compound is found to be losing mass gradually. Explain what is happening to the sample.
irina [24]

Explanation:

Uranium have an unstable nuclei , hence it  is a radioactive element , and radioactive element can undergo radioactive decay like the alpha decay , beta decay .

Radioactive decay is a spontaneous breakdown of the atomic nucleus which , results in the release of energy along with radioactive particles , like alpha , beta , gamma etc .

Hence ,

The mass is lost from a sample of uranium .

3 0
3 years ago
A given atom has 3 protons, 4 neutrons, and 3 electrons. Describe how you can use those three values to describe the structure,
ELEN [110]
Charge # = protons - electons 

Mass # = protons + neutrons 

so that would be 

3-3= charge#
3+4= mass#
3 0
2 years ago
Write the electrons configuration for an atom of an element whose atomic number is 8
Basile [38]
The electron configuration for a atom whose element has a atomic number of 8 (Oxygen) is 2,6
6 0
3 years ago
A solution is made by combining 500 mL of 0.10 M HF (Ka=7.2 x 10^-4) with 300 mL of 0.15 M NaF. What is the pH of the resulting
n200080 [17]

Answer:

b) 3.10

Explanation:

HF ⇄ H + + F

Using Henderson-Hasselbalch Equation:

pH = pKa + log [A-]/[HA].

Where;

pKa = Dissociation constant = -log Ka

Hence, pKa of HF = -log 7.2 x 10^-4 = 3.14266

[A-] = concentration of conjugate base after dissociation = moles of base/total volume

          = 0.15 x 0.3/0.8

               = 0.05625 M

[HA] = concentration of the acid = moles of acid/total volume

             = 0.10 x 0.5/0.8

                    = 0.0625 M

Note: <em>Total volume = 500 + 300 = 800 mL = 0.8 dm3</em>

pH = 3.14266 + log [0.05625/0.0625]

      = 3.14267 + (-0.04575749056)

           = 3.09691250944

<em>From all the available options below:</em>

<em>a) 2.97 </em>

<em>b) 3.10 </em>

<em>c) 3.19 </em>

<em>d) 3.22 </em>

<em>e) 3.32</em>

The correct option is b.

4 0
3 years ago
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