Question

Calculate the number of cells in a hummingbird assuming the mass of an average cell is ten times the mass of a bacterium

Answer 1

Answer:

$4\times 10^{12}$

Explanation:

Given that, the mass of an average cell is 10 times the mass of a bacterium.

And we know that the mass of the bacterium is,

$m_{B} =10^{-15}kg$

Now, the mass of an average cell can be calculate by the mass of bacterium,

$m_{c}=10\times m_{B}\\m_{c}=10\times 10^{-15}kg\\m_{c}=10^{-14}kg$

And the average mass of the humming bird is,

$m_{H} =4\times 10^{-2}kg$

And also we know that,

The no cell is defined as the ratio of mass of an object to the mass of the average cell.

Mathematically,

$N=\frac{m_{H}}{m_{c}}$

Therefore,

$N=\frac{4\times 10^{-2}kg}{10^{-14}kg}\\ N=4\times 10^{12}$

Therefore, the number of cell in the humming bird is $4\times 10^{12}$