A boxed 12.0 kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an ang
1 answer:
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Answer:
d= 1650 km.
Explanation:
- Assuming that sound waves travel along a straight line at a constant speed of 346 m/s, we can find the time needed for the sound to travel the distance of 1.9 m between the astronauts, just applying the definition of average velocity, as follows:
- The electromagnetic waves travel in free space at the same speed of light in vacuum ( since light is a electromagnetic wave indeed), i.e., 3*10⁸ m/s.
- Applying the same formula than in (1) we can solve for the distance d, as follows:
Answer:
104
Explanation:
U = Energy stored in the solenoid = 6.00 μJ = 6.00 x 10⁻⁶ J
i = current flowing through the solenoid = 0.4 A
L = inductance of the solenoid
Energy stored in the solenoid is given as
U = (0.5) L i²
6.00 x 10⁻⁶ = (0.5) L (0.4)²
L = 75 x 10⁻⁶
Inductance is given as
l = length of the solenoid = 0.7 m
N = number of turns
r = radius = 5.00 cm = 0.05 m
Area of cross-section is given as
A = πr²
A = (3.14) (0.05)²
A = 0.00785 m²
Inductance is given as
N = 73
Winding density is given as
density = n =
n =
n = 104