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alina1380 [7]
3 years ago
15

an experiment is designed to see if the shells of sea snails are weakened by exposure to sea water which is more acidic than nor

mal. shells are placed in normal sea water, sea water that is more acidic than normal, and sea water that is more basic than normal. the shells are checked every day at 8 am. which of the following is the best hypothesis for this experiment? the shells in the normal sea water will be the strongest. if the shells are exposed to sea water that is more acidic than normal, then they will be weaker. the shells in the sea water that is more basic than normal will be stronger. if the shells are affected by the level of acidity, then they will be weaker.
Physics
1 answer:
Naily [24]3 years ago
7 0
Since the statement of the problem is to determine if levels of acidity in sea water affect the strength of a sea snail's shell, then the best statement of hypothesis should be:

"<span> if the shells are affected by the level of acidity, then they will be weaker.</span>"

That hypothesis refers directly to the theory being questions in the problem.

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Sveta_85 [38]

Answer:

I would say the answer is A... but I'm not so sure ....

8 0
2 years ago
You illuminate the grating in a spectrometer at normal incidence θi=0° with a beam of light that has a wavelength of 6562.8 Å. T
monitta

Answer:

a) θ₁ = 23.14 ° , b) θ₂ = 51.81 °

Explanation:

An address network is described by the expression

     d sin θ = m λ

Where is the distance between lines, λ is the wavelength and m is the order of the spectrum

The distance between one lines, we can find used a rule of proportions

     d = 1/600

     d = 1.67 10⁻³ mm

    d = 1-67 10⁻³ m

Let's calculate the angle

    sin θ = m λ / d

    θ  = sin⁻¹ (m λ / d)

First order

    θ₁ = sin⁻¹ (1 6.5628 10⁻⁷ / 1.67 10⁻⁶)

    θ₁ = sin⁻¹ (3.93 10⁻¹)

    θ₁ = 23.14 °

Second order

     θ₂ = sin⁻¹ (2 6.5628 10⁻⁷ / 1.67 10⁻⁶)

     θ₂ = sin⁻¹ (0.786)

     θ₂ = 51.81 °

3 0
3 years ago
A 53.0-kg skater is traveling due east at a speed of 2.90 m/s. A 72.0-kg skater is moving due south at a speed of 6.20 m/s. They
soldier1979 [14.2K]

Answer:

a.\thta=71^{\circ}

b.v_f=3.78 m/s

Explanation:

We are given that

m_1=53 kg

v_1=2.9 m/s

m_2= 72 kg

v_2=6.2 m/s

a.We have to find the angle

\theta=tan^{-1}{\frac{m_2v_2}{m_1v_1}=\frac{72(6.2)}{53(2.9)}=71^{\circ}

\theta=71^{\circ}

b. We have to find the speed v_f

According to law of conservation of momentum

m_1v_1=(m_1+m_2)v_fcos\theta

53(2.9)=(53+72)v_fcos 71^{\circ}=40.7 v_f

v_f=\frac{153.7}{40.7}=3.78 m/s

3 0
3 years ago
A comet is in an elliptical orbit around the sun. its closest approach to the sun is a distance of 4.5 1010 m (inside the orbit
barxatty [35]

r1 = 5*10^10 m , r2 = 6*10^12 m

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4 0
3 years ago
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Assoli18 [71]

Answer:

Hence the pressure is 3\times 10^5 Pa

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We know work done is

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The change in the volume at constant pressure is

ΔV= W/P

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