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3 years ago

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What makes science different from other fields of knowledge like art or philosophy?

1 answer:

makkiz [27]3 years ago

5 0

As opposed to art or philosophy, science is an objective phenomenon. It deals with something which is verifiable, meaning that it can be tested, and it is based on facts, which are true and can be proven. On the other hand, art is highly subjective, which means that it can be interpreted in many different ways. Science is more concrete and testable, whereas art and philosophy lie in the domain of the abstract.

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Suppose an element had an atomic number of 52. How many protons would that element have?

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The element would have 52 protons because atomic number gives protons.

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If a cup of coffee is at 90°C and a person with a body temperature of 36°C touches it, how will heat flow between them?

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B: from the cup to the hand.

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A 100-W (watt) light bulb has resistance R=143Ω (ohms) when attached to household current, where voltage varies as V=V0sin(2πft)

Phantasy [73]

Complete Question

A 100-W (watt) light bulb has resistance R=143Ω (ohms) when attached to household current, where voltage varies as V=V0sin(2πft), where V0=110 V, f=60 Hz. The power supplied to the bulb is P=V2R J/s (joules per second) and the total energy expended over a time period [0,T] (in seconds) is $U = \int\limits^T_0 {P(t)} \, dt$

Compute U if the bulb remains on for 5h

Answer:

The value is $U = 7.563 *10^{5} \ J$

Explanation:

From the question we are told that

The power rating of the bulb is $P = 100 \ W$

The resistance is $R = 143 \ \Omega$

The voltage is $V = V_o sin [2 \pi ft]$

The energy expanded is $U = \int\limits^T_0 {P(t)} \, dt$

The voltage $V_o = 110 \ V$

The frequency is $f = 60 \ Hz$

The time considered is $t = 5 \ h = 18000 \ s$

Generally power is mathematically represented as

$P = \frac{V^2}{ R}$

=> $P = \frac{( 110 sin [2 \pi * 60t])^2}{ 144}$

=> $P = \frac{ 110^2 [ sin [120 \pi t])^2}{ 144}$

So

$U = \int\limits^T_0 { \frac{ 110^2* [sin [120 \pi t])^2}{ 144}} \, dt$

=> $U = \frac{110^2}{144} \int\limits^T_0 { ( sin^2 [120 \pi t]} \, dt$

=> $U = \frac{110^2}{144} \int\limits^T_0 { \frac{1 - cos 2 (120\pi t)}{2} } \, dt$

=> $U = \frac{110^2}{144} \int\limits^T_0 { \frac{1 - cos 240 \pi t)}{2} } \, dt$

=> $U = \frac{110^2}{144} [\frac{t}{2} - [\frac{1}{2} * \frac{sin(240 \pi t)}{240 \pi} ] ]\left | T} \atop {0}} \right.$

=> $U = \frac{110^2}{144} [\frac{t}{2} - [\frac{1}{2} * \frac{sin(240 \pi t)}{240 \pi} ] ]\left | 18000} \atop {0}} \right.$

$U = \frac{110^2}{144} [\frac{18000}{2} - [\frac{1}{2} * \frac{sin(240 \pi (18000))}{240 \pi} ] ]$

=> $U = 7.563 *10^{5} \ J$

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3 years ago

temperatura en la ciudad de la página madrugada y 2 grados bajo cero y a las 8 de la mañana sube a 6 grados y luego ya a las 10

vivado [14]

Answer:

kjkjnklhklsehfiodxlfngioduherl

Explanation:

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Which is the correct answer?

Nezavi [6.7K]

Answer:

Point A

Explanation:

The work done by stretching or compressing a spring is given by E=1/2kx²

The potential energy is numerically equal to the work done.

This means that the higher the bigger the value of the extension, x, the higher the energy contained.

In this scenario the modulus of x is considered.

Among the given values of x the modulus of -5 is the largest.

thus it gives the highest value of energy.

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3 years ago