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jek_recluse [69]
3 years ago
6

If the unit for force is f, the unit for velocity is v and the unit for time t, then the unit for momentum is

Physics
1 answer:
ASHA 777 [7]3 years ago
5 0
The answer is m I believe
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What is net force?
kramer

Answer:

A. The sum of all the forces acting on an object.

3 0
3 years ago
If a racquet ball hits the wall with 20 N of force, how much force will it bounce back with?
loris [4]

Answer:

-20N

Explanation:

The racquet ball will bounce back with the same force.

This is in compliance with newton's third law of motion:

  "action and reaction are equal but opposite"

If the ball hits the wall with an action force of 20N, the reaction force will be -20N.

The negative indicates an oppositely directed force.

8 0
3 years ago
a 15 year old broke into a store with his buddies one of the older boys shot and killed the store owner what the text says about
Tom [10]
He’s gonna be charged with aggravated robbery with deadly assault an a weapon
8 0
3 years ago
I need help ASAP please............
aniked [119]

Answer:

A satellite orbiting earth 1

Your shoulder 3

f=m x a 2

A soccer ball 2

A magician 3

When you paddle 3

A picture 1

Earth 1

A rocket 1

A speed skater 2

Explanation:

Law 1 states an object at rest , stay at rest and an object in motion stays in motion unless acted on by another force.

Law 2 states that the acceleration of an object depends on its mass and force applied.

Law 3 states every action creates an equal and opposite reaction.

6 0
3 years ago
A typical 100-watt light bulb consumes 100 j of energy per second. If a light bulb converts all of this energy to 400 nm light
VladimirAG [237]

The missing question is: how many photons are produced per second?

Answer:

2.0\cdot 10^{20}

Explanation:

The energy of a photon is given by

E_1 = \frac{hc}{\lambda}

where

h is the Planck constant

c is the speed of light

\lambda is the wavelength of the photon

In this problem, the photons have wavelength

\lambda = 400 nm = 400 \cdot 10^{-9} m, so each photon has an energy of

E_1 = \frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{400\cdot 10^{-9}}=4.97\cdot 10^{-19} J

The total energy emitted by the bulb in 1 second is

E = 100 J

Therefore, the number of photons emitted per second is

n=\frac{E}{E_1}=\frac{100}{4.97\cdot 10^{-19}}=2.0\cdot 10^{20}

3 0
3 years ago
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