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Lostsunrise [7]
3 years ago
6

I need help ASAP please............

Physics
1 answer:
aniked [119]3 years ago
6 0

Answer:

A satellite orbiting earth 1

Your shoulder 3

f=m x a 2

A soccer ball 2

A magician 3

When you paddle 3

A picture 1

Earth 1

A rocket 1

A speed skater 2

Explanation:

Law 1 states an object at rest , stay at rest and an object in motion stays in motion unless acted on by another force.

Law 2 states that the acceleration of an object depends on its mass and force applied.

Law 3 states every action creates an equal and opposite reaction.

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Light of wavelength 560 nm passes through a slit of width 0. 170 mm. (a) the width of the central maximum on a screen is 8. 00 m
faltersainse [42]

The distance between slit and the screen is 1.214m.

To find the answer, we have to know about the width of the central maximum.

<h3>How to find the distance between slit and the screen?</h3>
  • It is given that, wavelength 560 nm passes through a slit of width 0. 170 mm, and the width of the central maximum on a screen is 8. 00 mm.
  • We have the expression for slit width w as,

                           w=\frac{2*wavelength*d}{a}

where, d is the distance between slit and the screen, and a is the slit width.

  • Thus, distance between slit and the screen is,

                           d=\frac{w*a}{2*wavelength} =\frac{8*10^{-3}*0.17*10^{-3}}{560*10^{-9}*2} \\\\d=1.214m

Thus, we can conclude that, the distance between slit and the screen is 1.214m.

Learn more about the width of the central maximum here:

brainly.com/question/13088191

#SPJ4

3 0
2 years ago
A roller coaster takes energy to make the first rise, but then it should be able to run the course of the track without any inpu
den301095 [7]
I would say that this is the first law of thermodynamics.
6 0
4 years ago
Read 2 more answers
If railroad tracks were built over the boundary of two plates what would happen to the railroad tracks as the plates moved
Oliga [24]
The railroad tracks will move with the plate boundaries
6 0
4 years ago
how can there be so many different substances in the world if there are only a few elements that are common? 
LuckyWell [14K]
-- If there are only  <em>10</em>  elements in the universe that can make compound molecules, and a compound molecule can be formed by combining  1,  2,  3, or  4  different elements, then that's already the possibility of  at least 400 different molecules.

-- There are many more than  10  elements that can combine to form compound molecules.

-- Every single "<em>organic</em>" molecule, of which there are thousands, is the combination of <em>carbon</em> with other elements.

-- Most all of the substances that can be distilled out of oil, including the paraffin waxes, the alcohols, gasoline, kerosene, butane, propane, octane, and natural gas, are made of just carbon, hydrogen, and oxygen, only with different numbers of each one. 

-- Plastics, drugs, rubber, and DNA are examples of molecules that are made of <em>hundreds</em> of atoms.
3 0
3 years ago
For years, the tallest tower in the United States was the Phoenix Shot Tower in Baltimore, Maryland. The shot tower was used fro
Mariulka [41]

Answer:

The velocity of the droplet right before it hits the ground is 40.08 m/s.

Explanation:

To determine the velocity of the droplet right before it hits the ground,

From one of the equations of kinematic for free fall motions,

v = u + gt

Where v is the final velocity

u is the initial velocity

g is acceleration due to gravity (take g = 9.8 m/s²)

and t is time

For the question, v is the velocity of the droplet right before it hits the ground.

u = 0 m/s (Since the molten lead was dropped from rest)

Therefore,

v = gt

First, we will determine the time t

Also, from one of the equations of kinematic for free fall motions,

h = ut + 1/2(gt²)

u = 0 m/s

From the question, the molten lead was dropped from the top of the 82.15 m tall tower, therefore

h = 82.15

Hence,

82.15 = 0×t + 1/2 (9.8 × t²)

82.15 = 1/2 (9.8 × t²)

82.15 = 4.9 t²

t² = 82.15/4.9

∴ t = 4.09 secs

Now, for the velocity v, of the droplet right before it hits the ground,

Recall

v = gt

Then,

v = 9.8 × 4.09

v = 40.08 m/s

Hence, the velocity of the droplet right before it hits the ground is 40.08 m/s.

5 0
3 years ago
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