Answer:
a. It always points perpendicular to the contact surface.
Explanation:
"Normal" means perpendicular. Normal forces are always perpendicular to the contact surface.
Answer: Wernicke's aphasia
Explanation:
John recently suffered a blow to his head. Since then, he finds it difficult to comprehend what others say to him. He also finds it difficult to express his thoughts and cannot seem to find the right words to say while speaking. However, he can speak freely with proper syntax. In this scenario, John is most likely suffering from Wernicke's aphasia.
Wernicke's aphasia occurs when the leftward side of the middle of the brain is damaged or has been altered. An individual who suffers from Wernicke's aphasia will have difficulty in speaking in meaningful and coherent sentences or may have difficulty in understanding the speech of others.
Answer:
80m/s
Explanation:
to find it you have to work it out by using the formula distance divided by speed to find time.
Applicable linear expansion equation:
ΔL = αΔTL
In which
ΔL = change in length, α = Linear expansion coefficient of steel, ΔT = change in temperature, L = original length
Therefore,
ΔL = 12*10^-6*(18.5-(-3))*1410 = 0.36378 m
Answer:
9.51
Explanation:
The distance s is given by:
![s(t) = \sqrt{151^2 + (vt)^2}](https://tex.z-dn.net/?f=s%28t%29%20%3D%20%5Csqrt%7B151%5E2%20%2B%20%28vt%29%5E2%7D)
The change in distance is given by the time derivative of s:
![\frac{ds}{dt} = \frac{v^2t}{\sqrt{151^2 + (vt)^2}}](https://tex.z-dn.net/?f=%5Cfrac%7Bds%7D%7Bdt%7D%20%3D%20%5Cfrac%7Bv%5E2t%7D%7B%5Csqrt%7B151%5E2%20%2B%20%28vt%29%5E2%7D%7D)
For the time t you solve the equation of distance x for time:
![x = vt => t = \frac{x}{v}](https://tex.z-dn.net/?f=x%20%3D%20vt%20%3D%3E%20t%20%3D%20%5Cfrac%7Bx%7D%7Bv%7D)
Plugging in for t:
![\frac{ds}{dt}(t=\frac{x}{v})=\frac{vx }{\sqrt{151^2 + x^2}}=9.51](https://tex.z-dn.net/?f=%5Cfrac%7Bds%7D%7Bdt%7D%28t%3D%5Cfrac%7Bx%7D%7Bv%7D%29%3D%5Cfrac%7Bvx%20%7D%7B%5Csqrt%7B151%5E2%20%2B%20x%5E2%7D%7D%3D9.51)